Power alcohol is a mixture of petrol and alcohol in the ratio:

The formula for allyl alcohol is- 

The -OH group of an alcohol or the -COOH group of a carboxylic acid on can be replaced

by -Cl using

p-nitrophenol is stronger acid than phenol because nitro group is:

The most acidic compound among the following is- 

Which of the following has highest boiling point?

Tautomerism is not exhibited by-

The correct order of the acidic strength among for the above compounds is -

The boiling point of ethanol is higher than that of dimethyl ether due to presence of-                                            

The compound B formed in the following sequence of reactions,

CH₃CH₂CH₂OH$\stackrel{{\mathrm{PCl}}_5}{\to }$A$\stackrel{\mathrm{Alc}.\mathrm{NaOH}}{\to }$B will be:

Ethyl alcohol is denatured by:

Chlorobenzene reacts with Mg in dry ether to give a compound (A) which further reacts

with ethanol to yield     

 can be repared from williamson's synthesis using

Methanol and ethanol can be distinguished by the following:

CH₃MgBr + Cyclopentanone $\stackrel{H_{2}O}{\to }$A $\stackrel{HBr}{\to }$B$\stackrel{Mg/ether}{\to }$C$\underset{H_{3}O}{\overset{HCHO}{\to }}$D,

The product 'D' in the above-mentioned reaction is-

The reaction that does not give benzoic acid as the major product is-

Consider the following alcohols,

I. 

II. 

III. 

IV. 

Ease of dehydration of above alcohols will be in the order of-

The number of  moles of HI consumed in above reaction is -

R-CH₂-CH₂OH can be converted into RCH₂CH₂COOH. The correct sequence of reagents is: 

The strongest acid among the following aromatic compounds is -

$\underset{\mathrm{Acetone}}{\overset{{\left[{\left({\mathrm{CH}}_3\right)}_3\mathrm{CO}\right]}_3\mathrm{Al}}{\to }}X$

The product (x) of this reaction is 

The major product in the acid catalysed dehydration of  would be

Which of the following reactions will give 2° chiral alcohol as one or more of major organic products?

(1)
(2)
(3)
(4)	None

The major product of the following reaction sequence will be

$$\begin{gathered} \underset{\left(1\right)}{\overset{\mathbf{PhCOCl}\mathbf{ }\mathbf{/}\mathbf{ }\mathbf{Pyridine}\mathbf{ }}{\to }} \underset{\left(2\right)}{\overset{\mathit{C}{\mathit{H}}_{\mathbf{3}}\mathit{C}\mathit{O}\mathit{C}\mathit{l}\mathit{ }\mathbf{/}\mathit{A}\mathit{l}\mathit{C}{\mathit{l}}_3}{\to }} \\ \underset{\left(3\right)}{\overset{\mathit{Z}\mathit{n}\mathbf{-}\mathit{H}\mathit{g}\mathit{ }\mathbf{/}\mathit{H}\mathit{C}\mathit{l}\mathbf{/}\mathbf{∆}}{\to }} \underset{\left(4\right)}{\overset{\mathit{B}{\mathit{r}}_{\mathbf{2}}\mathit{ }\mathbf{/}\mathit{F}e}{\to }} \end{gathered}$$

1.
2.
3.
4.

In the following reactions X, Y and Z are respectively :

	X	Y	Z
(1)
(2)
(3)
(4)

An aromatic compound A (C₈H₁₀O) gives following tests with the given reagents.

The structure of  'A' is -

1.
2.
3.
4.

Compound Y,  C₇H₈O is insoluble in water, dil HCI and aqueous NaHCO₃. It dissolves in dilute NaOH. When Y is treated with bromine water it is converted rapidly into a compound of formula C₇H₅OBr₃.  The structure of Y is -

1.
2.
3.
4.

Compounds I and II can be distinguished by using reagent

i.  

ii. 

iii.  

The correct order of dehydration of compounds (i), (ii) and (iii) by conc. H₂SO₄ is-

Product (x) will be:

(a) 

(b) 

(c) 

(d)