When CH₃CH₂CHCl₂ is treated with NaNH₂, the product formed is                             

Chlorobenzene reacts with Mg in dry ether to give a compound (A),
'A' further reacts with ethanol to yield -                                                                                                    

R-CH₂-CCl₂-R $\stackrel{\mathrm{Reagent}}{\to }$R-C$\equiv$C-R. The reagent is

Ethyl chloride is converted into diethyl ether by -                                                  

The alkyl halide is converted into an alcohol by                                    

The addition of Br₂ on cis-but-2-ene gives:

The number of different substitution products possible when ethane is allowed to react with bromine in sunlight are:

 , Cl obtained by chlorination of n-butane, will be                

The reactivity order of halides for dehydrohalogenation is 

In ${\mathrm{S}}_{{\mathrm{N}}^2}$ reactions, the correct order of reactivity for the following compounds : ${\mathrm{CH}}_3\mathrm{Cl}$, ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$, ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$ and ${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$ is :

Action of RMgX with vinyl chloride gives:

What would be the product formed when 1-bromo-3-chlorocyclobutane reacts with two equivalents of metallic sodium in ether?

X $\stackrel{{\mathrm{Cl}}_2}{\to }$ Benzotrichloride $\stackrel{\mathrm{Hydrolysis}}{\to }$ Y

X and Y respectievely are:

Benzene on reaction with a mixture of HNO₃ and H₂SO₄ followed by reaction of Cl₂/FeCl₃ gives:

A yellow precipitate is obtained when aqueous ${\mathrm{AgNO}}_3$ is added to a solution of the compound:

End product D of the following reaction will be

(1)
(2)
(3)
(4)

In the following sequences of reactions;

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{KOH}(\mathrm{alc}.)}{\to }$(A)$\stackrel{{\mathrm{Br}}_2}{\to }$(B)$\stackrel{{\mathrm{NaNH}}_2/{\mathrm{NH}}_3}{\to }$(C)

the end product (C) is:

Which is gem dihalide?

Friedel-Craft's reaction of bromobenzene with methyl iodide gives:

Benzyl chloride (C₆H₅CH₂Cl) can be prepared from toluene by chlorination with:

When vinyl chloride is passed through alcoholic KOH solution:

Identify 'Z' in the following reaction series,

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br} \stackrel{\mathrm{aqueous} \mathrm{NaOH}}{\to }\left(X\right) \underset{\mathrm{Heat}}{\overset{{\mathrm{Al}}_2{\mathrm{O}}_3}{\to }} \left(Y\right) \stackrel{\mathrm{HOCl}}{\to }\left(Z\right)$:

The reaction, RCl +NaI $\stackrel{\mathrm{Acetone}}{\to }\mathrm{R}-\mathrm{I}$ + NaCl is known as:

Elimination of HBr from 2-bromobutane results in the formation of:

(CH₃)₃CMgCl on reaction with D₂O gives:

Benzoyl Chloride is prepared from benzoic acid by:

In the following sequences of reactions;

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}\stackrel{\mathrm{KOH}(\mathrm{alc}.)}{\to }$(A)$\stackrel{\mathrm{HBr}}{\to }$(B)$\stackrel{\mathrm{KOH}\left(\mathrm{aq}\right)}{\to }$ (C)

the product (C) is:

Iodoform can be prepared from all except :

The alkyl halide that can not give a white precipitate with an alcoholic ${\mathrm{AgNO}}_3$solution is:

Identify (Z) in the following reaction reaction series,

C₂H₅I $\underset{\mathrm{KOH}}{\overset{\mathrm{Alcoholic}}{\to }}$(X) $\underset{}{\overset{{\mathrm{Br}}_2}{\to }}$(Y) $\stackrel{\mathrm{excess} \mathrm{KCN}}{\to }$(Z):