Hydrogenation of vegetable ghee at 25⁰C reduces pressure of H₂ from 2 atom to 1.2 atom in 50 minute. The rate of reaction in terms of molarity per second is:

A hypothetical reaction, A₂ +B₂ $\to$ 2AB mechanism as given below;

A₂ $\rightleftharpoons$A+ A          ............(Fast)

A+B₂ → AB + B   ............(Slow)

A+ B → AB         ............(Fast)

The order of the overall reaction is:

Following mechanism has been proposed for a reaction,

2A+B $\to$D+E

A+B$\to$ C+D    ...(Slow)

A+ C$\to$ E         ...(Fast)

The rate law expression for the reaction is:

In gaseous reactions important for the understanding of the upper atmosphere H₂O and O react bimolecularly to form two OH radicals. $∆$H for this reaction is 72kJ at 500 K and E_a is 77 kJ mol^-1, then E_a for the bimolecular recombination of two OH radicals to form H₂O and O is:

For a reaction A$\stackrel{ }{\to }$ Product, rate law is $-\frac{d\left[A\right]}{dt}=K[A{]}_0$. The concentration of A left after time t when $t=\frac{1}{K}$ is:

For an exothermic chemical process occurring in two steps as;

(i) A+B$\to$X(Slow)

(ii) X$\to$AB (Fast)

The progress of the reaction can be best described by:

For the non-stoichiometric reaction 2A + B $\to$ C +D, the following kinetic data were obtained in three separate experiments, all at 298 K.

The rate law for the formation of C is:

For the reaction N₂ + 3H₂ $\to$ 2NH₃, the rate $\frac{\mathrm{d}\left[{\mathrm{NH}}_3\right]}{\mathrm{dt}}$= 2 x 10^-4 M s^-1 .Therefore, the rate $\frac{-\mathrm{d}\left[{\mathrm{N}}_2\right]}{\mathrm{dt}}$ is given as:

If 'I' is the intensity of absorbed light and 'c' is the concentration of AB for the photochemical process AB + hv→  AB *, the rate of formation of AB * is directly proportional to:

Which curve represents zero order reaction?

In a reaction, the rate expression is, rate = K[A][B]^2/3[C]⁰ , the order of reaction is:

The rate of a reaction get doubles when the temperature changes from 7°C to 17°C. By what factor will it change for the temperature change from 17°C to 27°C?

In Arrhenius equation K = Ae^-E_a/RT, the quantity e^-E_a/kT is referred as:

For the elementary step,

(CH₃)_3.CBr(aq) → (CH₃)₃C⁺ (aq) + Br^- (aq) the molecularity is:

When ethyl acetate was hydrolysed in pressure of 0.1 N HCl, the rate constant was found to be 5.40 x 10^-5 sec^-1 . But when 0.1 N H₂SO₄ was used for hydrolysis, the rate constant was found to be 6.25 X10^-5sec^-1. Thus, it may be concluded that:

The half time of a second order reaction is:

The rate constant of a second-order reaction is 10^-2 mol^-1 litre s^-1 The rate constant expressed in cc molecule^-1min^-1 is:

The half-life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log 2 = 0.301):

A drop of solution (volume 0.05 mL) contains 3.0 x10^-6 mole of H⁺. If the rate constant of disappearance of H+ is 1.0x10⁷ mol litre sec?. How long would it take for H⁺ in drop to disappear?

A zero order reaction is one:

For A+B $\to$C+D, $∆$H = -20 kJmol^-1 the activation energy of the forward reaction is 85 kJ mol^-1. The activation energy for backward reaction is...... kJ mol^-1

Given that K is the rate constant for some order of any reaction at temprature T .Then the value of $\underset{t\to \infty }{lim}$ logK = (where A is the Arrhenius constant):

For the elementary reaction M $\to$ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is-

K for a zero-order reaction is 2 x10^-2 mol L^-1 sec^-1. If the concentration of the reactant after 25 sec is 0.5 M, the initial concentration must have been:

The rate constant for a second order reaction is 8x10^-5 M^-1 min^-1 . How long will it take a 1M solution to be reduced to 0.5M?

The activation energy for a reaction is 9.0 kcal/mol. The increase in the rate constant when its temperature is increased from 298K to 308K is:

In the following first order competing reactions:

A + Reagent $\to$ Product

B + Reagent $\to$ Product

The ratio of K₁/K₂ if only 50% of B will have been reacted when 94% of A has been reacted in same time is:

For a reversible reaction A $\underset{k_2}{\overset{k_1}{\rightleftharpoons }}$ B, Ist order in both the directions, the rate of reaction is given by:

The time for half-life of a first order reaction is 1 hr. What is the time taken for 87.5% completion of the reaction?

Which order of reaction obeys the relation t_1/2 = 1/Ka?