CO 2 H | CO 2 H + CH 2 | - OH 18 CH 2 - OH 18 → ∆ H + (A); Product (A) in the above mentioned reaction is:

C | ∥ O - O 18 - CH 2 | C ∥ O - O 18 - CH 2

C | ∥ 18 O - O - CH 2 | C ∥ 18 O - O - CH 2

H - O - C ∥ O - C ∥ O - O - CH 2 - CH 2 - OH

Chemistry - Alcoholsphenols Ethers - Quiz-5

0.092 g of a compound with the molecular formula C₃H₈O₃ reaction with an excess of CH₃MgI gives 67.00 mL of methane at STP. The number of active hydrogen atoms present in a molecule of the compound is:

0%
one
0%

two
0%

three
0%

four

Optically active 2-octanol rapidly loses its optical activity when exposed to :

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Dilute acid
0%

Dilute base
0%

Light
0%

Humidity

Product Z of above reaction is :

0%
1
0%
2
0%
3
0%
4

In each of the following groups, which is the strongest (best) nucleophile ?

(I)(1)H₃C-O^- (2) (3)H₃C-S^- in CH₃OH

(II)(1)OH^- (2) H₂O (3) ${NH}_{2}^{-}$ in DMF

(III) (1) (2) (3) CH₃O^- in DMSO

0%

() I,3; II,3; III,2
0%
() I,2; II,1; III,3
0%

() I,1; II,2; III,1
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() I,3; II,1; III,3

(A) on heating isomerizes to (B). What is the structure of (B) ?

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1
0%
2
0%
3
0%
4

Which of the following statements is true?

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CH₃CH₂S^- is both a stronger base and more nucleophilic than CH₃CH₂O^-
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CH₃CH₂S^- is a stronger base but is less nucleophilic than CH₃CH₂O^-
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CH₃CH₂S^- is a weaker base but is more nucleophilic than CH₃CH₂O^-
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CH₃CH₂S^- is both a weaker base and less nucleophilic than CH₃CH₂O^-

Ether cannot be produced as a major product by the reaction of-

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CH₃CH₂Cl + Ag₂O(dry) $\to$
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(CH₃)₃CCl + CH₃CH₂O^-Na⁺ $\to$
0%
0%

Predict the product when the given compound reacts with LiAlH₄ :

The labeled -O¹⁸ will be in:

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H₂O
0%

Methyl benzoate
0%

Both 1 and 2
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Benzoic acid

$\begin{matrix} \underset{|}{{CO}_{2} H} \\ {CO}_{2} H \end{matrix} + \begin{matrix} \underset{|}{{CH}_{2}} & - & \overset{18}{OH} \\ {CH}_{2} & - & \overset{18}{OH} \end{matrix} \to_{∆}^{H^{+}}$ (A);

Product (A) in the above mentioned reaction is:

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0%
$\begin{matrix} \overset{O}{\overset{∥}{\underset{|}{C}}} & - & \overset{18}{O} & - & \underset{|}{{CH}_{2}} \\ \underset{O}{\underset{∥}{C}} & - & \underset{18}{O} & - & {CH}_{2} \end{matrix}$
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$\begin{matrix} \overset{^{18} O}{\overset{∥}{\underset{|}{C}}} & - & O & - & \underset{|}{{CH}_{2}} \\ \underset{^{18} O}{\underset{∥}{C}} & - & O & - & {CH}_{2} \end{matrix}$
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$\begin{matrix} H & - & O & - & \overset{O}{\overset{∥}{C}} & - & \overset{O}{\overset{∥}{C}} & - O & - & {CH}_{2} & - & {CH}_{2} & - & OH \end{matrix}$

The compound that is most prone to oxidation is -

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CH₃-CHOH-CH₃
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0%
CH₃-CH₂-O-CH₂-CH₃
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(P); Product (P) is:

Which of the following react with HBr at faster rate?

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1
0%
2
0%
3
0%
4

Above conversion can be carried out by-

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NaBH₄
0%

LiAlH₄
0%

PCC
0%

KMnO₄

$\to_{H_{2} {SO}_{4} / ∆}^{2 {CH}_{3} OH}$ (A);

The product (A) in the above-mentioned reaction is:

Identify the major product,

$\overset{{LiAlH}_{4}}{\to}$ (A) Major; Product (A) is:

0%

()
0%

()
0%

()
0%

()

$\overset{H_{2} {CrO}_{4}}{\to}$ (A) Product (A) is:

0%

() No reaction
0%

()
0%

()
0%

()

Consider the following alcohols,

(I) (II)

(III) (IV)
The order of decreasing reactivities of these alcohols towards nucleophilic substitution with HBr is:-

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() III>I>IV>II
0%
() III>I>II>IV
0%

() I>III>IV>II
0%
() I>III>II>IV

The structure of A in the above mentioned reaction is -

$\to_{(2) H^{+}, H_{2} O}^{(1) EtLi (3.5 eq)} (A) 65 % Yield$ ; Chemist added extra 0.5 mole of Et-Li in above reaction to obtain product (A), which is ?