Identify the compound C in the following sequence :

$({\mathrm{CH}}_3{)}_2{\mathrm{CHCH}}_2\mathrm{C}\equiv \mathrm{N}\stackrel{\mathrm{HCl}, {\mathrm{H}}_2\mathrm{O}}{\to }$compound A $\underset{2. {\mathrm{H}}_2\mathrm{O}}{\overset{1. {\mathrm{LiAlH}}_4}{\to }}$compound B $\underset{{\mathrm{CH}}_2{\mathrm{Cl}}_2}{\overset{\mathrm{PCC}}{\to }}$compound C 

(a)  $$\begin{gathered} O \\ \left|\right| \\ {\left(C{H}_3\right)}_{2}CHCC{H}_3 \end{gathered}$$

                                 
(b) $$\begin{gathered} O \\ \left|\right| \\ {\left(C{H}_3\right)}_{2}CHC{H}_{2}COH \end{gathered}$$

(c) $$\begin{gathered} O \\ \left|\right| \\ {\left(C{H}_3\right)}_{2}CHC{H}_{2}CH \end{gathered}$$                 

(d) $$\begin{gathered} O \\ \left|\right| \\ {\left(C{H}_3\right)}_{2}CHC C{H}_{2}OH \end{gathered}$$

What is compound Z?

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}\stackrel{\mathrm{NaCN}}{\to }$$\mathrm{X}\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }}$$\mathrm{Y}\underset{{\mathrm{H}}^{+}}{\overset{{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}}{\to }}$Z

(a) $$\begin{gathered} O \\ \left|\right| \\ C{H}_{3}CH-CHCOH \end{gathered}$$           

(b) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CH}={\mathrm{NOCH}}_2{\mathrm{CH}}_3$

(c) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{CH}({\mathrm{OCH}}_2{\mathrm{CH}}_3{)}_2$         

(d)  $$\begin{gathered} O \\ \left|\right| \\ C{H}_{3}C{H}_{2}COC{H}_{2}C{H}_3 \end{gathered}$$

Identify (A).

(a)      (b)     (c)      (d) 

$\underset{\left(\mathrm{i}\right){\mathrm{H}}^{+}}{\overset{\left(\mathrm{i}\right)\mathrm{KBrO},∆}{\to }} \left(\mathrm{X}\right)\stackrel{∆}{\to \left(\mathrm{Y}\right)}$

Hence the product (Y) in the above sequence of reactions, is :

(a)  (b)   (c)   (d) 

The action of bromine water (excess) on salicylic acid results in the formation of:-

An organic compound having the molecular formula C₈H₁₀O on being heated with I₂ and dilute NaOH gives a yellow precipitate. The expected compound is:

The Birch reduction of benzoic acid gives:-
(a)  
(b)  
(c)  
(d) 

ph-CHO  +   2 $\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }$ major product of this reaction is:

$\underset{\left(2\right) {\mathrm{H}}_3{\mathrm{O}}^{\oplus }}{\overset{\left(1\right) {\mathrm{KMnO}}_4, {\mathrm{HO}}^{-}, ∆}{\to }}$

The labelled carbon goes with:

$$\begin{gathered} 1. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{O}}_2\mathrm{H} \\ 2. \stackrel{14}{\mathrm{C}}{\mathrm{O}}_2 \\ 3. \mathrm{Ph}-\stackrel{14}{\mathrm{C}}{\mathrm{H}}_2-{\mathrm{CO}}_2\mathrm{H} \\ 4. \stackrel{14}{\mathrm{C}}{\mathrm{H}}_4 \end{gathered}$$

Which of the following acid gives positive Tollen's reagent test.

Acetaldehyde and benzaldehyde can be differentiated by:

1. Fehling test

PCl₅ reacts with propanone, to give:

When vapours of acetic acid are passed over.....at $300°\mathrm{C}$ we get acetone.

Formaldehyde is not used in:

Ketones can be prepared by:

Cyclohexanone is subjected to reduction by ${\mathrm{NaBH}}_4$. The product formed is:

Schiff's reagent is:

Which of the following reaction is a condensation reaction?

Which of the following is correct for carbonyl compounds?

Compound having molecular formula ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$ may be:

Which of the following would undergo aldol condensation?

Dry distillation of barium salt of Hexane-1,2-dicarboxylic acid gives :

Paraldehyde is:

Paraldehyde is used as a:

A typical compound undergoes Cannizzaro's reaction and aldol condensation. It is:

Formaldehyde when treated with KOH gives methanol and potassium formate. The reaction is known as:

In the reaction, P is: 

Acetaldehyde reacts with PCl₅, to give:

The reaction  is an example of:

Stephen's reaction is reduction of: