Benzamide  $\stackrel{{\mathrm{Br}}_2, \mathrm{NaOH}}{\to }$ A $\underset{2. {\mathrm{H}}_3{\mathrm{PO}}_2}{\overset{1. {\mathrm{HNO}}_2}{\to }}$ Benzene $\stackrel{{\mathrm{CH}}_3\mathrm{Cl}, {\mathrm{AlCl}}_3}{\to }$B

A and B in the above reaction sequence are -

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{NaCN}}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CN}\stackrel{{\mathrm{OH}}^{-}, \mathrm{Partial} \mathrm{hydrolysis}}{\to }\mathrm{A}\underset{\mathrm{NaOH}}{\overset{{\mathrm{Br}}_2}{\to }}\mathrm{B}$

The molecular formulae of A, and B in the above reaction are-

$$\begin{gathered} 1. {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{COOH}, \mathrm{and} {\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{Br}\right)\mathrm{COOH} \\ 2. {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{COOH}, \mathrm{and} {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{COBr} \\ 3. {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CONH}}_2, \mathrm{and} {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2 \\ 4. {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CONH}}_2, \mathrm{and} {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2 \end{gathered}$$

The formula of A and B in the following reaction is -

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl} \stackrel{\mathrm{CuCN}}{\to } {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CN} \stackrel{{\mathrm{H}}_2\mathrm{O} /{\mathrm{H}}^{+}}{\to } \mathrm{A} \stackrel{{\mathrm{NH}}_3 ,∆}{\to }\mathrm{B}$

 $$\begin{gathered} 1. {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COOH}, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CONH}}_2 \\ 2. {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COOH}, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2 \\ 3. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{NH}}_2, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{N}=\mathrm{NH} \\ 4. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{\mathrm{NH}}_2, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{N}=\mathrm{NH} \end{gathered}$$

The molecular formulae of A and B in the following are-
$CH_3CH_2Br\xrightarrow{KCN}CH_3CH_2CN\xrightarrow{LiAlH_4}\\A\xrightarrow {HNO_2,~OCo}B$

$\mathrm{A}\stackrel{{\mathrm{NH}}_3, ∆}{\to } {\mathrm{CH}}_3{\mathrm{CONH}}_2 \stackrel{\mathrm{NaOBr}}{\to } \mathrm{B}\stackrel{{\mathrm{NaNO}}_2/\mathrm{HCl}}{\to } {\mathrm{CH}}_3\mathrm{OH}$

A and B in the above reaction sequence are

$$\begin{gathered} 1. {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}, \mathrm{and} {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{N}}_2\mathrm{Cl} \\ 2. {\mathrm{CH}}_3\mathrm{COOH}, \mathrm{and} {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2 \\ 3. {\mathrm{CH}}_3\mathrm{COOH}, \mathrm{and} {\mathrm{CH}}_3{\mathrm{NH}}_2 \\ 4. {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}, \mathrm{and} {\mathrm{CH}}_3{\mathrm{NH}}_2 \end{gathered}$$

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NO}}_2\stackrel{\mathrm{Sn}/\mathrm{HCl}}{\to } \mathrm{A}\stackrel{{\mathrm{HNO}}_2, 273\mathrm{K}}{\to } {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl}\stackrel{{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH}}{\to } \mathrm{B}$

A and B in the above reaction sequence are -

$$\begin{gathered} 1. {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}=\mathrm{NH}, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_6 \\ 2. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2, \mathrm{and} \mathrm{p}-\mathrm{hydroxyazobenzene} \\ 3. {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}=\mathrm{NH}, \mathrm{and} \mathrm{p}-\mathrm{hydroxyazobenzene} \\ 4. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2, \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH} \end{gathered}$$

Consider the following statements related to ammonolysis.

a. Cleavage of C-X bond by ammonia takes place.

b. Ammonolysis produces primary, secondary, tertiary amine and quaternary ammonium salt.

c. In ammonolysis, ammonia is a nucleophile.

The true statement(s) are-

The correct statements among the following is -

The incorrect statement among the following is -

Identify the compound that will react with Hinsberg's reagent to give a solid which dissolves in alkali.

The reagent 'R' in the given sequence of a chemical reaction is : 

Aniline with excess of methyl iodide in the presence of sodium carbonate solution gives: