Chlorobenzene →HNO3, H2SO4 X →H2/Pd Y
X and Y in the above sequence are-
1-chloro-4-nitrobenzene, and nitrobenzene
1-chloro-3-nitrobenzene, and 4-chloroaniline
1-chloro-4-nitrobenzene, and 4-chloroaniline
1-chloro-3-nitrobenzene, and nitrobenzene
Benzamide →Br2, NaOH A →2. H3PO21. HNO2 Benzene →CH3Cl, AlCl3B
A and B in the above reaction sequence are -
Chlorobenzene and aniline
Aniline and toluene
p-Methylaniline and chlorobenzene
None of the above
CH3CH2I→NaCNCH3CH2CN→OH-, Partial hydrolysisA→NaOHBr2B
The molecular formulae of A, and B in the above reaction are-
1. CH3CH2COOH, and CH3CH(Br)COOH2. CH3CH2COOH, and CH3CH2COBr3. CH3CH2CONH2, and CH3CH2NH24. CH3CH2CONH2, and CH3CH2CH2NH2
The formula of A and B in the following reaction is -
C6H5N2Cl →CuCN C6H5CN →H2O /H+ A →NH3 ,∆B
1. C6H5COOH, and C6H5CONH22. C6H5COOH, and C6H5NH23. C6H5CH2NH2, and C6H5CH2N=NH4. C6H5CH2NH2, and C6H5CH2N=NH
The molecular formulae of A and B in the following are-\(CH_3CH_2Br\xrightarrow{KCN}CH_3CH_2CN\xrightarrow{LiAlH_4}\\A\xrightarrow {HNO_2,~OCo}B\)
A→NH3, ∆ CH3CONH2 →NaOBr B→NaNO2/HCl CH3OH
A and B in the above reaction sequence are
1. CH3CH2OH, and CH3CH2N2Cl2. CH3COOH, and CH3CH2NH23. CH3COOH, and CH3NH24. CH3CH2Br, and CH3NH2
Identify compounds A, B, and C
A = , B = , C =
C6H5NO2→Sn/HCl A→HNO2, 273K C6H5N2Cl→C6H5OH B
1. C6H5N=NH, and C6H62. C6H5NH2, and p-hydroxyazobenzene3. C6H5N=NH, and p-hydroxyazobenzene4. C6H5NH2, and C6H5OH
Consider the following statements related to ammonolysis.
a. Cleavage of C-X bond by ammonia takes place.
b. Ammonolysis produces primary, secondary, tertiary amine and quaternary ammonium salt.
c. In ammonolysis, ammonia is a nucleophile.
The true statement(s) are-
a, b
a, b, c
a, c
b
The correct statements among the following is -
Coupling reaction is an example of an electrophilic substitution reaction.
Azo dye contains -N=N- linkage.
p-Aminoazobenzene is obtained when diazonium salt reacts with an aniline.
All of the above
The incorrect statement among the following is -
pKb of aniline is more than methylamine.
Ethylamine is soluble in water whereas aniline is not.
Aniline undergo Friedel-Crafts reaction
Gabriel phthalimide synthesis is preferred for synthesizing primary amines.
Identify the compound that will react with Hinsberg's reagent to give a solid which dissolves in alkali.
The reagent 'R' in the given sequence of a chemical reaction is :
HI
CuCN/KCN
H2O
CH3CH2OH
Aniline with excess of methyl iodide in the presence of sodium carbonate solution gives:
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