What will be the product when aniline reacts with benzoyl chloride ?

The correct increasing order of basic strength for the following compounds is .

In the nitration of benzene using a mixture of conc. H₂SO₄ and conc. HNO₃,

the species that initiates the reaction is -

$$\begin{gathered} 1. {\mathrm{NO}}_2 \\ 2. {\mathrm{NO}}^{+} \\ 3. {\mathrm{NO}}_2^{+} \\ 4.\hspace{0.17em}{\mathrm{NO}}_2^{-} \end{gathered}$$

Match the compounds given in Column I with the items given in Column II.

Codes

          A         B          C           D

Assertion(A): N-ethylbenzene sulphonamide is soluble in alkali.

Reason(R): Hydrogen attached to nitrogen in sulphonamide is strongly acidic.

Assertion(A): Only a small amount of HCI is required in the reduction of nitro compounds with iron scrap and HCI in the presence of steam.

Reason(R): FeCl₂ formed gets hydrolyzed to release HCI during the reaction.

$$\begin{gathered} \left(i\right) Aromatic amine + Nitrous acid \to A \\ \left(ii\right) Aliphatic amine + Nitrous acid \to B \end{gathered}$$

The A and B in the above reactions are -

Amines are less acidic than alcohols of comparable molecular masses because

In the conversion of  Nitromethane to methylamine, the reagent used is -

$$\begin{gathered} 1. SOC{l}_2 \\ 2. NaN{H}_2 \\ 3. PC{l}_5 \\ 4. Sn/HCl \end{gathered}$$

An aromatic compound ‘A’ on treatment with ammonia and heating forms compound ‘B’ which on heating with Br₂ and KOH forms a compound ‘C’ of molecular formula C₆H₇N. The Substrate A is -

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give -

A compound A when reacted with PCl₅ and then with ammonia gave B. B when treated with bromine and caustic potash produced C. C on treatment with NaNO₂ and HCl at $0°$C and then boiling produced ortho-cresol. Compound A is:

An organic compound ($C_3{H}_{9}N$) (A), when treated with nitrous acid, gave an alcohol and N₂ gas was evolved. (A) on warming with CHCl₃ and caustic potash gave (C) which on reduction gave isopropylmethylamine. The structure of (A) is

Which of the following compounds is most basic ?

D

If D is N-methyl aniline than A is:

Aniline reacts with $B{r}_2$ water, and $NaN{O}_2/HCl$ gives respectively :

Aniline when diazotized in cold and then treated with dimethyl aniline gives a coloured product. Its structure would be :- 

The reaction which gives isocyanide is :

The final product C, obtained in this reaction, would be :

A method for the identification of primary, secondary and tertiary amines is -

Aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis because -

The primary amine is -

Which of the following is a secondary amine is -

$$\begin{gathered} 1. {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_2{\mathrm{NH}}_2 \\ 2. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3 \\ 3. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NHCH}}_3 \\ 4. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2 \end{gathered}$$

The tertiary amine is-

$$\begin{gathered} 1. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3 \\ 2. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2 \\ 3. \mathrm{m}-{\mathrm{BrC}}_6{\mathrm{H}}_4{\mathrm{NH}}_2 \\ 4. \mathrm{None} \mathrm{of} \mathrm{these} \end{gathered}$$

The chemical test used to distinguish between aniline and benzylamine is-

The chemical test used to distinguish between aniline and N-methyl aniline is-

The chemical test used to distinguish between methylamine and dimethylamine is-

X, Y, and Z in the above sequence are -

X, and Y in the following sequence are

Benzyl chloride $\stackrel{\mathrm{KCN}}{\to }$ X $\stackrel{LiAl{H}_4}{\to }$ Y

The product X and Y are -