A gaseous mixture contains O2 and N2 in the ratio 1:4 by weight. Then the ratio of their number of molecules in the mixture is

  • 3:32

  • 7:32

  • 1:4

  • 3:16

1cc N2O at STP contains 

  •  1.32224×1023 electrons

  •  6.0222400×1023 molecules

  •  1.8224×1022 atoms

  • All of the above

A 5 molar solution of H2SO4 is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be -

  • 0.5 N

  • 1.0 N

  • 2.5 N

  • 5 N

If 0.50 mole of BaCl2 is mixed with 0.20 mole of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is -

  • 0.10

  • 0.20

  • 0.30

  • 0.40

lf equal moles of water and urea are taken in a vessel,The mass percentage of urea in the solution will be -

  • 22.086

  • 11.536

  • 46.146

  • 76.92

Sodium bicarbonate on heating decomposes to form sodium carbonate, CO2 and water. If 0.2 moles of sodium bicarbonate is completely decomposed, how many moles of sodium carbonate is formed?

  • 0.1

  • 0.2

  • 0.05

  • 0.025

A purified pepsin was subjected to amino acid analysis. The amino acid present in the smallest amount was lysine, C6H14N2O2 and the amount of lysine was found to be 0.431g per 100 g of protein. The minimum molecular mass of protein is

  • 34 u

  • 3400 u

  • 34,000 u

  • 3,400,000 u

The number of valence electrons present in 0.53 grams of Na2COis

  •  3.01×1023

  •  7.22×1022

  •  12.046×1023

  •  6.023×1023

At STP, the density of CCl4 vapour in g/L will be closest to

  • 8.67

  • 6.87

  • 3.67

  • 4.26

If 3.02×1019 molecules are removed from 98 mg of H2SO4, then the number of moles of H2SO4 left are -

  •  0.1×10-3

  •  9.5×10-4

  •  1.2×10-4

  •  0.5×10-3

A chloride of a metal (M) has 65.5% of chlorine. 100 ml of vapour of the chloride of metal at STP weighs 0.72 g. The molecular formula of this metal chloride is

  • MCl3 

  • MCl4 

  • M2Cl3 

  • MCl5 

The molality of 0.01 M Na2CO3 solution is -

(density of the solution is 1.1 g/ml)

  •  9×10-3

  •  1.8×10-3

  •  4.5×10-3

  •  1.1×10-3

The weight of 1x1023 molecules of CuSO4.5H2O is 

  • 34.42 g

  • 41.42 g

  • 54.44 g

  • 68.94 g

lf Nis Avogadro's number, then the number of valence electrons in 4.2 g of nitride ions (N3-) will be:

  • 3.2 NA

  • 1.6 NA

  • 2.4 NA

  • 1.2 NA

2. 1.01332 x 106 Pa

  • 1.01332 x 105 Pa

  • 4. 1.01332 x 108 Pa

  •  1.01332 x 10Pa

  • If the mass of air at sea level is 1034 g cm–2, pressure in pascal will be:

The SI unit of mass is:

  • Kilogram (kg)

  • Gram (g)

  • Pascal (Pa)

  • Kilometres (km)

ln the final answer of the expression

(29.2-20.2) (1.79×105)1.37

the number of significant figures after solving the expression is:

  • 2

  • 4

  • 6

  • 7

The volume of carbon dioxide gas evolved at STP by heating 7.3 g of Mg(HCO3)2 will be -

  • 1000 mL

  • 1120 mL

  • 2230 mL

  • 3240 mL

The amount of Zinc (atomic weight=65) necessary to produce 224 mL of H2 by the reaction with dilute suphuric acid will be 

  • 0.65 g

  • 7.6 g

  • 6.5 g

  • 8.5 g

On complete decomposition, the volume of CO2 released at STP on heating 9.85 g of BaCO3 (atomic mass, Ba=137) will be 

  • 1.12 L

  • 4.84 L

  • 2.12 L

  • 2.06 L

Specific volume of cylindrical virus particle is 6.02×10-2 cc/g. Whose radius and length are 7 Å and 10 Å respectively. If NA=6.02×1023, the molecular weight of virus is -

  •  15.4 kg/mol

  •  1.54×104 kg/mol

  •  4.68×104 kg/mol

  •  2.08×103 kg/mol

 The empirical formula of an oxide of iron, which has 69.9% iron and 30.1% oxygen by mass is -

  • FeO

  • Fe2O3

  • Fe3O4

  • Fe3O2

The mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molars aqueous solution would be -

Molar mass(sodium acetate) = 82.0245 g/mol

  • 17.86g

  • 31.76g

  • 20.34g

  • 15.38g

The concentration of 69% nitric acid (by mass) in a sample with a density of 1.41 g / mL will be-

  • 15.44 mol/L

  • 17.14 mol/L

  • 20.06 mol/L

  • 12.26 mol/L

The mass of ammonia produced when 2.00 × 103 g dinitrogen reacts with 1.00 ×103 g of dihydrogen is 

  • 2338.11 g

  • 2428.57 g

  • 2712.24 g

  • 2180.56 g

The total number of electrons present in 1.4 g of dinitrogen gas are -

  •  6.023 × 1023 electrons

  •  8.416 × 1022 electrons

  •  4.214 × 1023 electrons

  •  3.927 × 1024 electrons

If 1010 wheat grains are distributed each second, the time taken to distribute one Avogadro number of wheat grains would be -

1. 1.91 × 106 years2. 2.31 × 104 years3. 3.84 × 106 years4. 1.91 × 105 years

  • 1
  • 2
  • 3
  • 4

A reading on Fahrenheit scale is 200°F. The same reading on celsius scale will be :

  •  40°C
  •  94°C
  •  93°C
  •  30°C

If 500 mL of a 5 M solution is diluted to 1500 mL, the molarity of the resultant solution is 

  • 1.5 M

  • 1.66 M

  • 0.017 M

  • 1.59 M

The mass per cent of carbon in carbon dioxide is : 

  •   0.034%

  •   27.27%

  •   3.4%

  •   28.7%

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