The average atomic mass of chlorine using the following data would be -

Isotope

% Natural

Abundance

Molar

Mass

35Cl 75.7734.9689
37Cl 24.2336.9659
  • 38.4527 u

  • 37.4527 u

  • 36.4527 u

  •  35.4527 u

The number of moles of hydrogen atoms present in 3 moles of ethane (C2H6), will be-

  • 18.069 x 1023

  • 1.8 x 1023

  • 18

  • 6 x 1023

20 g of sugar is dissolved in enough water to make a final volume of 2L. The concentration of sugar (C12H22O11) in mol L–1  will be

2. 0.029 mol/L

  • 0.29 mol/L

  • 4. 0.032 mol/L

  • 0.35 mol/L

  • 4

If the density of methanol is 0.793 kg L–1, the volume needed for making 2.5 L of its 0.25 M solution would be 

2. 24.78 mL

  • 22.25 mL

  • 4. 252 mL

  •  25.22 mL 

  • 4

The level of contamination in water is 15 ppm (by mass of chloroform). Chloroform in the water sample would have a molality of

  • 3.25 x 10-4   

  •  1.5 x 10-3 

  •   7.5 x 10-3    

  • 1.25 x 10-4  

If the speed of light is 3.0 × 108 m s–1, then the distance covered by light in 2.00 nanoseconds will be -

  •  0.500 m

  •  0.600 m

  •  0.700 m

  •  0.800 m

In a reaction A + B2 →AB2, 
A will act as a limiting reagent if 
i. 300 atoms of A reacts with 200 molecules of B
ii. 2 mol A reacts with 3 mol B
iii. 100 atoms of A reacts with 100 molecules of B
iv. 5 mol A reacts with 2.5 mol B
v. 2.5 mol A reacts with 5 mol B
Choose the correct option

  •  (i), (ii)
  • (i), (ii), (v)
  •  (ii), (v)
  • All

If 10 volumes of H2 gas react with 5 volumes of O2 gas, the volumes of water vapor produced would be 

  • 9

  • 8

  • 10

  • 11

15.15 pm in the basic unit will be 

  • 1.515 x 10-12 m

  • 2.57 x 10-11 m

  • 2.87 x 10-11 m

  • 1.515 x 10-11 m

Which will have the largest number of atoms among the following.

  • 1 g Au (s)

  • 1 g Na (s)

  • 1 g Li (s)

  • 1 g of Cl2(g)

The molarity of a solution of ethanol in water having a mole fraction of ethanol is 0.040 (assume the density of water to be 1) would be -

  • 2.143 M

  • 2.314 M

  • 2.413 M

  • 2.141 M

The mass of one 12C atom in g is -

  •  1.393 x 10-23

  • 1.993 x 10-23

  •  1.773 x 10-23

  •  1.593 x 10-23

The number of significant figures present in the answer of the following calculations [ (i), (ii), (iii)]  are respectively -
i. 
0.02856 × 298.15 ×0.1120.5785
ii. 5 × 5.364
iii. 0.0125 +
0.7864 + 0.0215

  • 4, 4, 3
  • 3, 3, 4
  • 4, 3, 4
  • 3, 4, 4

The molar mass of naturally occurring Argon isotopes is 

Isotope Isotopic molar mass Abundance
36-Ar  35.96755 g mol–1 0.337%
38-Ar  37.96272 g mol–1  0.063%
40-Ar  99.600%

1. 49.99947 g mol-1 

  • 4. 45.59947 g mol-1  

  • 2. 39.99947 g mol-1  
  • 3. 35.59947 g mol-1  
  • 39.9624 g mol–1 

The highest number of atoms is present in -

(2) 52 u of He

 

  • 52 moles of Ar

  • (3) 52 g of He.

  • 3
  • All of the above have the same number of atoms

Burning a small sample of welding gas (constituted of C and H only)  in oxygen gives 3.38 g carbon dioxide, 0.690 g of water, and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. Molecular formula of welding gas would be -

  • C2H2

  • C2H6

  •  CH

  • C2H4

The mass of CaCO3 required to react completely with 25 mL of 0.75 M HCl according to the given reaction would be
CaCO3(s) + HCl(aq) ➡ CaCl2(aq) + CO2(g) + H2O(l) 

  •  0.36g

  •  0.09 g

  • 0.96 g

  •  0.66 g

Amount of HCl that would react with 5.0 g of manganese dioxide, as per the given reaction will be
4HCl(aq) + MnO2(s) ➡ 2H2O(l) + MnCl2(aq) + Cl2(2)

  • 4.8 g

  • 6.4 g

  • 2.8 g

  •  8.4 g

16 g of oxygen has the same number of molecules as in-

(a) 16 g of CO

(b) 28 g of N2

(c) 14 g of N2

(d) 1.0 g of H2

 

  • (a), (b)

  • (b), (c)

  • (c), (d)

  • (b), (d)

Unitless term among the following is/are-

(a) Molality

(b) Molarity

(c) Mole fraction

(d) Mass per cent

 

  • (a), (b)

  • (b), (c)

  • (c), (d)

  • (b), (d)

List I List II
a. Micro i. 10-15 m
b. Mega ii. 10-6 m
c. Giga iii. 106 m
d. Femto iv. 109 m

The correct match is 

  • a = i, b = iv, c = iii, d = ii
  •  a = iii, b = iv, c = ii, d = i
  • a = ii, b = iii, c = iv, d = i
  •  a = i, b = iii, c = iv, d = ii

Which of the following figures does not represent 1 mole of dioxygen gas at STP?

(a) 16 g of gas

(b) 22.7 L of gas

(c) 6.022×1023 dioxygen molecules

(d) 11.2 L of gas

The correct choice among the above is -

  • (a, b, c)

  • (a, b, d)

  • (b, c, d)

  • (a, c, d)

The numbers 234,000 and 6.0012 can be represented in scientific notation as -

  •  2.34×10-9 and 6×103

  • 0.234 ×10-6 and 60012×10-9

  •  2.34×10-9 and 6.0012×10-9

  • 2.34×105 and 6.0012×100

The number of significant figures in the numbers 5005, 500.0, and 126,000 are, respectively: 

  • 2, 4, and 3 

  • 4, 1, and 3 

  • 4, 4, and 6 

  • 4, 4, and 3 

0.50 mol Na2CO3 and 0.50 M Na2CO3 are different because -

 

  • Both have different amounts of Na2CO3

  • 0.50 mol is the number of moles and 0.50 M is the molarity

  • 0.50 mol Na2CO3 will generate more ions

  • None of the above

Round up the following number into three significant figures: 
i. 10.4107  ii. 0.04597 respectively  are 

  • 10.4, 0.0460
  • 10.41, 0.046
  • 10.0, 0.04
  • 10.4, 0.0467

The following data was obtained when dinitrogen and dioxygen react together to form different compounds:

Mass of dinitrogen  Mass of dioxygen
i. 14 g 16 g
ii. 14 g 32 g
iii. 28 g 32 g
iv. 28 g 80 g

The law of chemical combination applicable to the above experimental data is:

  • Law of multiple proportions
  • Law of constant composition
  • None of these.

  • Law of reciprocal proportions

An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] 

  • CH3

  • CH4

  • CH

  • CH2

The molecular formula of a commercial resin used for exchanging ions in water softening is C8H7SO3Na Mol. Wt. 206. The maximum uptake of Ca2+ ions by the resin when expressed in mole per gram resin is-

  •  1103

  •  1206

  •  2309

  •  1412

 SI unit of Mole fraction is -

  • Candela

  •  Nm–1

  • kg

  •  Unitless

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