In the hydrocarbon CH 3 -CH=CH-CH 2 -C ≡ CH The state of hybridisation of carbons 1,3 and 5 are in the following sequence

sp 2 , sp, sp 3 (2) sp, sp 3 , sp 2

sp, sp 2 , sp 3 (4) sp 3 , sp 2 , sp

The correct order of increasing thermal stability of K 2 CO 3 , MgCO 3 , CaCO 3 and BeCO 3 is:

BeCO 3 < MgCO 3 < CaCO 3 < K 2 CO 3

BeCO 3 < MgCO 3 < K 2 CO 3 < CaCO 3

MgCO 3 < BeCO 3 < CaCO 3 < K 2 CO 3

K 2 CO 3 < MgCO 3 < CaCO 3 < BeCO 3

Chemistry - Chemical Bonding Molecular Structure - Quiz-4

Which of the following is paramagnetic?

0%

CO
0%

$O_{2}^{-}$
0%

CN^-
0%

NO⁺

The correct order of solubility in an aqueous medium is:

0%

CuS > ZnS > Na₂S
0%

ZnS > Na₂S > CuS
0%

Na₂S > CuS > ZnS
0%

Na₂S > ZnS > CuS

XeF₂ is isostructural with :

0%

TeF₂
0%

ICI₂^-
0%

SbCl₃
0%

BCl₃

Which one of the following molecules contain no $π$ -bond?

0%

CO₂
0%

H₂O
0%

SO₂
0%

NO₂

Which one of he following pairs is isostructural (i.e., having the same shape and

hybridization)?

0%

[BCl₃ and BrCl₃]
0%

[NH₃ and ${NO}_{3}^{-}$ ]
0%

[NF₃ and BF₃]
0%

[ ${BF}_{4}^{-}$ and ${NH}_{4}^{+}$ ]

Considering the state of hybridisation of carbon atoms, find out the molecule among the

following which is linear.

0%

HC≡CH
0%

CH₂ = CH—CH₂—C = CH
0%

CH₃ — CH₂ — CH₂ — CH₃
0%

CH₃—CH = CH—CH₃

In which of the following pairs of molecules/ions, the central atoms have sp² hybridisation?

$1 . {NO}_{2}^{-} and {NH}_{3} 2 . {BF}_{3} and {NO}_{2}^{-} 3 . {NH}_{2}^{-} and H_{2} O 4 . {BF}_{3} and {NH}_{2}^{-}$

0%
1
0%
2
0%
3
0%
4

The correct increasing order of bond angles in the following species is:

2. ClO₂< Cl₂O < ${ClO}_{2}^{-}$

0%

Cl₂O < ClO₂< ${ClO}_{2}^{-}$
0%

4. ${ClO}_{2}^{-}$ < Cl₂O < ClO₂
0%

Cl₂O < ${ClO}_{2}^{-}$ < ClO₂
0%
4

The tendency of BF₃, BCl₃, and BBr₃ to behave as Lewis acid decreases in the sequence

0%

BCl₃ > BF₃ > BBr₃
0%

BBr₃ > BCI₃ > BF₃
0%

BBr₃ > BF₃ > BCl₃
0%

BF₃ > BCl₃ > BBr₃

Given the following hydrocarbon:

The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively :

0%

sp, sp³, sp² and sp³
0%

sp³, sp², sp² and sp
0%

sp, sp², sp² and sp³
0%

sp, sp² sp³ and sp²

What is the dominant intermolecular force on bond that must be overcome in converting

liquid CH₃OH to a gas?

0%

Hydrogen bonding
0%

Dipole-dipole interaction
0%

Covalent bonds
0%

London dispersion force

The angular shape of ozone molecule (O₃) consists of

0%

1 sigma and 2 pi bonds
0%

2 sigma and 2 pi bonds
0%

1 sigma and 1 pi bonds
0%

2 sigma and 1 pi bonds

In the hydrocarbon

CH₃-CH=CH-CH₂-C $\equiv$ CH

The state of hybridisation of carbons 1,3 and 5 are in the following sequence

0%

sp², sp, sp³
(2) sp, sp³, sp²
0%

6 5 4 3 2 1
0%

sp, sp², sp³
(4) sp³, sp², sp
0%
4

The correct order of increasing thermal stability of K₂CO₃, MgCO₃, CaCO₃ and BeCO₃is:

0%
BeCO₃ < MgCO₃ < K₂CO₃< CaCO₃
0%

BeCO₃ < MgCO₃ < CaCO₃ < K₂CO₃
0%

MgCO₃ < BeCO₃ < CaCO₃ < K₂CO₃
0%

K₂CO₃ < MgCO₃ < CaCO₃ < BeCO₃

Which among the following compounds has higher hydration energy than the lattice energy?

0%

BaSO₄
0%

MgSO₄
0%

CaSO₄
0%

SrSO₄

In which of the following molecules are all the bonds not equal ?

0%

ClF₃
0%

BF₃
0%

AlF₃
0%

NF₃

The electronegativity difference between N and F is greater than that between N and H yet the dipole moment of NH₃ (1.5 D) is larger than that of NF₃ (0.2 D). This is because:

0%

in NH₃ as well as in NF₃ the atomic dipole and bond dipole are in the same direction
0%
in NH₃ the atomic dipole and bond dipole are in the same direction whereas in NF₃these are in opposite directions
0%
in NH₃ as well as NF₃ the atomic dipole and bond dipole are in opposite directions
0%
in NH₃ the atomic dipole and bond dipole are in the opposite directions whereas in NF₃ these are in the same directions

The correct order of electronegativity of hybrid orbitals of carbon is:

0%

sp>sp²<sp³
(2) sp>sp²>sp³
0%
2
0%

sp<sp²>sp³
(4) sp<sp²<sp³
0%
4

Which of the following species has a linear shape?

0%

${NO}_{2}^{-}$
0%

SO₂
0%

${NO}_{2}^{+}$
0%

O₃

Which of the following is the most basic oxide?

0%
Al₂O₃
0%

Sb₂O₃
0%

Bi₂O₃
0%

SeO₂

Which of the following is not a correct statement?

0%

The electron-deficient molecules can act as Lewis acids
0%

The canonical structures have no real existence
0%

Every AB₅ molecule does, in fact, have square pyramid structure
0%

Multiple bonds are always shorter than corresponding single bonds

The number unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number 16 is :

0%

2
0%

3
0%

4
0%

1

Which of the following is not isostructural with SiCl₄?

(a) SCl₄ (b) ${SO}_{4}^{2 -}$ (c) ${PO}_{4}^{3 -}$ (d) ${NH}_{4}^{+}$

0%
1
0%
2
0%
3
0%
4

Least stable hydride is:

0%

stannane
(2) silane
(3) plumbane
(4) germane
0%
2
0%
3
0%
4

Correct order of strength of H-bond in the following compounds is :

0%

$H_{2} O > H_{2} O_{2} > H F > H_{2} S$
0%

$H F \geq H_{2} O_{2} > H_{2} O > H_{2} S$
0%

$H F > H_{2} O > H_{2} S > H_{2} O_{2}$
0%

$H F > H_{2} O_{2} > H_{2} O > H_{2} S$

Molecule having non-polar as well as polar bonds but the molecule as a whole is polar:

0%

() $S_{2} F_{2}$
0%

() $N_{2} O_{4}$
0%

() ${Si}_{2} H_{6}$
0%

() $I_{2} {Cl}_{6}$

Choose the correct statement regarding $S e O C l_{2}$ molecule:

0%

It does not contain a plane of symmetry
0%

$' Cl - \hat{Se} - Cl' bond is greater than' Cl - \hat{Se} - O' bond angle$
0%

Lone pair has greater than 33.3% s-character
0%

Central atom used one d-orbital in bonding.

Which of the following compounds can form H-bonding with each other?

0%

() $C H_{3} C O O H a n d H_{2} O$
0%

() Phenol and $C H_{4}$
0%

() $C H F_{3} a n d a c e t o n e$
0%

() $P H_{3} a n d H F$

Which of the following compound is planar and non-polar?

0%

$X e O_{4}$
0%

$S f_{4}$
0%

$X e f_{4}$
0%

$C f_{4}$

The incorrect statement(s) regarding ${CX}_{3}$ species is:

0%

If electronegativity of surrounding element 'X' is less than 2.5, then central carbon atom used almost 33% s-character in their hybrid bonding orbitals
0%

If electronegativity of surrounding element 'X' is more than 2.5, then central carbon atom used almost 25% s-character in their hybrid bonding orbitals
0%

If 'X' is 'F', then species should be polar and pyramidal
0%

If 'X' is H, then species should be polar and planar

0:0:1

Practice Chemistry Quiz Questions and Answers

0:0:1

Practice Chemistry Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.