having low value of dipole moment than N H 3

having more dipole moment than N H 3

Allyl cyanide; C 3 H 5 CN has- 3. 8 sigma bonds and 5 pi bonds

2. 9 sigm bonds, 3 pi bonds and 1 lone pairs

4. 8 sigma bonds, 3 pi bonds and 4 non-bonding eletrons.

In the structure of H 2 C S F 4 , to decide the plane in which C = S is present the following bond angle value are given Axial FSF angle i d e a l i s e d = 180 ° ⇒ 170 ° Equatorial FSF angle i d e a l i s e d = 120 ° ⇒ 97 ° After deciding the plane of double bond, which of the following statements is correct?

Two C-H bonds are in the same plane of axial S-F bonds.

Two C-H bonds are in the same plane of equatorial S-F bonds.

Total five atoms are in the same plane.

Equatorial S-F bonds are perpendicular to plane of π bond.

Chemistry - Chemical Bonding Molecular Structure - Quiz-9

$N F_{3}$ is:

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non-polar compound
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electrovalent compound
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having low value of dipole moment than $N H_{3}$
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having more dipole moment than $N H_{3}$

Polarization of electrons in acrolein may be written as:

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() $\overset{δ^{-}}{C} H_{2} = C H - \overset{δ^{+}}{C} H = O$
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() $\overset{δ^{-}}{C} H_{2} = C H - C H = \overset{δ^{+}}{O}$
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() $\overset{δ^{-}}{C} H_{2} = \overset{δ^{+}}{C} H - C H = O$
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() $\overset{δ^{+}}{C} H_{2} = C H - C H = \overset{δ^{-}}{O}$

$P C l_{5}$ exists but $N C l_{5}$ does not because:

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Nitrogen has no vacant d-subshells .
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$N C l_{5}$ is unstable .
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Nitrogen atom is much smaller than p .
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Nitrogen is highly inert .

The bond angle between two hybrid orbitals is $105^{°}$ . The % s character in orbital is-

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Between 30-31%
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Between 9- 12%
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Between 25 -26%
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Between 22-23%

Which bond angle would result in the maximum dipole moment for the triatomic molecule $X Y_{2}$

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$90^{°}$
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$120^{°}$
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$150^{°}$
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$180^{°}$

When $O_{2}$ is adsorbed on a metallic surface, electron transfer occurs from the ,metal to $O_{2}$ . The wrong statements(s) regarding this adsorption is (are):

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$O_{2}$ is physisorbed
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Heat is released
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Occupancy of $π * 2 p$ of $O_{2}$ is increased
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Bond length of $O_{2}$ is increased

Born Haber cycle is used to determine:

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lattice energy
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electron affinity
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ionization energy
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either of them

The molecule having the smallest bond angle is-

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${PCl}_{3}$
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${NCl}_{3}$
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${AsCl}_{3}$
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${SbCl}_{3}$

Select the most ionic and most covalent compounds respectively from the following.

$C r O_{5}, M n_{2} O_{7}, P b O, P_{4} O_{10}, S n O_{2}$

(A) $C r O_{5}, M n_{2} O_{7}$ (B) $P b O, M n_{2} O_{7}$

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1
0%
2
0%
3
0%
4

In which of the following sets the central atom of each member involves $s p^{3}$ hybridisation?

(A) $I {O_{4}}^{‐} I C {l_{4}}^{‐} a n d I {F_{4}}^{+}$ (B) $X e O_{3}, X e O_{4}, X e F_{4}$

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1
0%
2
0%
3
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4

In which of the following groups all the members have linear shape?

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$N O_{2}, {N_{3}}^{‐}, I C {l_{2}}^{+}$
(2) ${N_{3}}^{‐}, {I_{3}}^{‐}, N {O_{2}}^{+}$
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2
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$X e F_{2}, C_{2} H_{2}, S O_{2}$
(4) $C O_{2}, B e C l_{2}, S n C l_{2}$
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4

Which reaction involves a change in the HYBRIDIZATION for the under lined geometry?

(A) $B F_{3} + F \to B {F_{4}}^{-}$ (B) $N H_{3} + H^{+} \to N {H_{4}}^{+}$

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1
0%
2
0%
3
0%
4

The ${BF}_{3}$ is a planar molecule whereas ${NF}_{3}$ is pyramidal because:

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$B - F$ bond is more polar than $N - F$ bond.
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Boron atom is bigger than nitrogen atom.
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Nitrogen is more electronegative than boron.
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${BF}_{3}$ has no lone pair but ${NF}_{3}$ has a lone pair of electrons.

Which of the following statement is true for $I O_{2} {F_{2}}^{-}$ according to VSEPR theory?

(A) The lone pair and two I-O double bonds occupy the equatorial positions of trigonal
bipyramid.

(B) It has $s p^{3}$ hybridization and is T-shaped.

(D) (A) and (C) both

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1
0%
2
0%
3
0%
4

Which of the species has the maximum number of lone pairs of electrons on the central
atom?

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$X e O F_{4}$
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$I {F_{4}}^{+}$
0%

$X e F_{2}$
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$B r F_{3}$

The molecule having a high dipole moment among the following is-

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H₂S
0%

BF₃
0%

CO₂
0%

CCl₄

Allyl cyanide; C₃H₅CN has-

3. 8 sigma bonds and 5 pi bonds

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2. 9 sigm bonds, 3 pi bonds and 1 lone pairs
0%
2
0%

4. 8 sigma bonds, 3 pi bonds and 4 non-bonding eletrons.
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1. 9 sigma bons and 4 pi bonds

The hybridization of carbon atoms in C-C single bond of HC≡C-CH=CH₂ is-

0%

$s p^{3} - s p^{3}$
0%

$s p^{2} - s p$
0%

$s p - s p$
0%

$s p^{3} - s p$

C-C bond in C₂H₆ undergoes heterolytic fission, the hybridisation of carbon is/are-

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$s p^{2}$
0%

$s p^{3}$
0%

$s p^{2}, s p^{3}$
0%

$s p, s p^{2}$

A diatomic molecule, among the following species, that only has $π$ bonds according to Molecular Orbital Theory (MOT) is -

0%

Be₂
0%

O₂
0%

N₂
0%

C₂

In the structure of $H_{2} C S F_{4}$ , to decide the plane in which C = S is present the following bond angle value are given

Axial FSF angle $(i d e a l i s e d = 180 °)$ $\Rightarrow 170 °$

Equatorial FSF angle $(i d e a l i s e d = 120 °)$ $\Rightarrow 97 °$

After deciding the plane of double bond, which of the following statements is correct?

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Two C-H bonds are in the same plane of axial S-F bonds.
0%

Two C-H bonds are in the same plane of equatorial S-F bonds.
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Total five atoms are in the same plane.
0%

Equatorial S-F bonds are perpendicular to plane of $π$ bond.

Which of the following are isoelectronic and isostructural ?

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$N {O_{2}}^{+}, C O_{2}$
(2) $N {O_{3}}^{-}, B F_{3}$
0%
2
0%

$N H_{3}, C {H_{3}}^{-}$
(4) All of these
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4

The correct order of acidic strength is :

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${Cl}_{2} O_{7} > {SO}_{2} > P_{4} O_{10}$
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${CO}_{2} > N_{2} O_{5} > {SO}_{3}$
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${Na}_{2} O > MgO > {Al}_{2} O_{3}$
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$K_{2} O > CaO > MgO$

In which of the following molecules / ions are all the bond angles not equal?

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$S i F_{4}$
(2) $I C {l_{4}}^{-}$
0%
2
0%

$S F_{4}$
(4) $P C {l_{4}}^{+}$
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4

What is the correct order from the weakest to the strongest carbon-oxygen bond for the following species?

$C O, C O_{2}, C {O_{3}}^{2 -}, C H_{3} O H$

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$C H_{3} O H < C {O_{3}}^{2 -} < C O_{2} < C O$
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$C O < C O_{2} < C {O_{3}}^{2 -} < C H_{3} O H$
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$C H_{3} O H < C {O_{3}}^{2 -} < C O < C O_{2}$
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$C H_{3} O H < C O_{2} < C {O_{3}}^{2 -} < C O$

According to Molecular orbital theory which of the following statement is incorrect?

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LUMO level for $C_{2}$ molecule is $σ_{2 p x}$ orbital.
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In $C_{2}$ molecules both the bonds $π$ are bonds.
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$C_{2}$ is paramagnetic but ${C_{2}}^{2 -}$ is diamagnetic.
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In ${C_{2}}^{2 -}$ ion there is one $σ$ and two $π$ bonds.

Match the ionization processes listed in column – I with the changes observed as listed in
column-II. For this use the codes given below:

Column- I Column - II

(a) $N_{2} \to N_{2}^{+}$ (p) Bond order increases and magnetic property is changed.

(b) ${O_{2}}^{+} \to {O_{2}}^{2 +}$ (q) Bond order decreases and magnetic property is changed.

(d) $N O^{-} \to N O$ (s) Bond order decreases and magnetic property is changed.

Note : Here change in magnetic property refers to change from diamagnetic to paramagnetic
or paramagnetic to diamagnetic.

a b c d

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s q p r
0%
s p q r
0%
r q s p
0%
p s q r

A diatomic molecule has a dipole moment of 1.2 D. If its bond length is equal to 10 ^-10 m , then the fraction of an electronic charge on each atom will be:

0%

42%
0%

52%
0%

37%
0%

25%

Arrange the following molecules from most to least polar.

$C H_{4} C F_{2} C l_{2} C F_{2} H_{2} C C l_{4} C C l_{2} H_{2} I I I I I I I V V$

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III>V>II > IV=I
(2) II>IV>III>IV>I
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2
0%

III>II>V>IV>I
(4) V>III>II>IV=I
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4

Which of the following statements is correct?

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${(C H_{3})}_{3}$ COH is less acidic than ${(C H_{3})}_{3}$ SiOH.
0%

Like CO, its analogue of Si is not stable.
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In phosgene, C-O bond length is longer than expected while C-Cl bond length is shorter.
0%

All of these

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Practice Chemistry Quiz Questions and Answers

0:0:1

Practice Chemistry Quiz Questions and Answers

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