Chemistry - Classification Elements Periodicity Properties - Quiz-6

There are four elements 'p', 'q', 'r' and 's' having atomic number Z-1, Z, Z+1 and Z+2 respectively. If there element 'q' is an inert gas, select the correct answers from the following statements.

(i) 'p' has most negative electron gain enthalpy in the respective period.

(ii) 'r' is an alkali metal.

(iii) 's' exists in +2 oxidation state.

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(i) and (ii)
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(ii) and (iii)
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(i) and (iii)
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(i), (ii) and (iii)

Given below are four orders for the size of the species. Choose the correct ones :

(a) ${Al}^{3 +} < {Mg}^{2 +} < {Na}^{+} < F^{-}$

(b) ${Al}^{3 +} < {Mg}^{2 +} < {Li}^{+} < K^{+}$

(d) $Mg > Al > Si > P$

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(a), (b) & (c)
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(b), (c) & (d)
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(a), (c)
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(a), (b), (c) & (d)

Which of the following orders are correct for the ionization energies?

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(A) 1, 2 and 4 (B) 1, 3 and 4
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(C) 1, 2 and 3 (D) 1, 2, 3 and 4
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$B a < S r < C a$ (2) $S^{2 -} < S < S^{2 +}$
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(3) $C < O < N$ (4) $M g < A l < S i$

The electron gain enthalpies of halogens in kJ mol^-1 are given below.

F =-332, Cl =-349, Br =-325, I =-295.

The lesser negative value for F as compared to that of Cl is due to:

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Smaller electronegativity value of F than Cl.
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1 & 2 both
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Strong electron-electron repulsions in the compact 2p-subshell of F.
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Weak electron-electron repulsions in the bigger 3p-subshell of Cl.

Which of the following statements are correct ?

(i) Generally the radius trend and the ionization energy trend across a period are exact opposites.

(ii) Electron affinity values of elements may be exothermic (negative) or endothermic (positive)

(iii) The first ionization energy of sulphur is higher than that of phosphorus ?

(iv) $T e^{2 -} > I^{-} > C s^{+} > B a^{2 +}$ represents the correct decreasing order of ionic radii.

(A) (i), (iii) and (iv) (B) (ii), (iii) and (iv)

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1
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2
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3
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4

The correct order among the following options is:

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F>N>C>Si>Ga - Non-metallic character.
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F>Cl>O>N - Oxidising property.
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C<Si>P>N - Electron affinity value.
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All of the above.

If the same element is forming oxides in different oxidation states then :

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that oxides will be neutral in nature in which element will be in its highest oxidation state.
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that oxide will be highest acidic in nature in which element will be in this highest oxidation state.
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that oxide will be amphoteric in nature in which element will be in its highest oxidation state.
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that oxide will be highly basic in nature in which element will be in its highest oxidation state.

Assertion : The $5^{t h}$ period of periodic table contains 18 elements and not 32.

Reason : n = 5, –1 = 0, 1, 2, 3. The order in which the energy of available orbits 4d, 5s and 5p increases is 5s < 4d < 5p and the total number of orbitals available are 9 and thus 18 electrons can be accommodated.

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If both the ssertion and the reason are true and the reason is a correct explanation of the assertion
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If oth the assertion and reason are true but the reason is not a correct explanation of the assertion
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If the assertion is true but the reason is false
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If both the assertion an reason are false

Assertion : :The 4f- and 5f- inner transition series of elements are placed separately at
the bottom of the periodic table.

Reason : (i) This prevents the undue expansion of the periodic table i.e., maintains its structure.
(ii) This preserve the principle of classification by keeping elements with similar properties in a single column.

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If both the ssertion and the reason are true and the reason is a correct explanation of the assertion
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If oth the assertion and reason are true but the reason is not a correct explanation of the assertion
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If the assertion is true but the reason is false
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If both the assertion an reason are false

Assertion : Manganese (atomic number 25 ) has a less favourable electron affinity than its neighbours on either side because.

Reason : The Manganese has stable, ${[A r]}^{18} 3 d^{5} 4 s^{2}$ electrons configuration.

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If both the ssertion and the reason are true and the reason is a correct explanation of the assertion
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If oth the assertion and reason are true but the reason is not a correct explanation of the assertion
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If the assertion is true but the reason is false
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If both the assertion an reason are false

Assertion: Fluorine forms only one oxoacid, HOF.

Reason: Fluorine has a small size and high electronegativity.

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Both assertion and reason are true and the reason is the correct explanation of assertion.
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Both assertion and reason are true and the reason is not the correct explanation of assertion.
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Assertion is true but the reason is false.
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Assertion is false but the reason is true.

Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is

1 s^{2} 2 s^{2} 2 p^{3}

, the simplest formula for this compound is :

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${Mg}_{2} X_{3}$
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${MgX}_{2}$
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${Mg}_{2} X$
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${Mg}_{3} X_{2}$

Which, of the following, order of ionic radii is correctly represented?

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$H^{-} > H^{+} > H$
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$N a^{+} > F^{-} > O^{2 -}$
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$F^{-} > O^{2 -} > N a^{+}$
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$N^{3 -} > M g^{2 +} > A l^{3 +}$

Be²⁺ is isoelectronic with which of the following ions?

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$H^{+}$
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$L i^{+}$
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$N a^{+}$
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$M g^{2 +}$

The correct order of decreasing second ionization enthalpy of Ti(22), V(23), Cr (24) and Mn(25) is

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Cr > Mn > V > Ti
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V > Mn > Cr > Ti
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Mn > Cr > Ti > V
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Ti > V > Cr > Mn

Among the following, the most characteristic oxidation states for lead and tin are, respectively:

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+4, +2
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+2, +4
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+4, +4
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+2, +2

Identify the correct order of the size of the following :

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$C a^{2 +} < K^{+} < A r < S^{2 -} < C l^{-}$
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$C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}$
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$A r < C a^{2 +} < K^{+} < C l^{-} < S^{2 -}$
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$C a^{2 +} < A r^{+} < K^{+} < C l^{-} < S^{2 -}$

Which one of the following orders is not in accordance with the property stated against?

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$F_{2} > C l_{2} > B r_{2} > I_{2} : O x i d i \sin g p o w e r$
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$H l > H B r > H C l > H F : A c i d i c p r o p e r t y i n w a t e r$
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$F_{2} > C l_{2} > B r_{2} > I_{2} : E l e c t r o n e g a t i v i t y$
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$F_{2} > C l_{2} > B r_{2} > I_{2} : B o n d d i s s o c i a t i o n e n e r g y$

For the second period elements, the correct increasing order of first ionisation enthalpy is:

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Li<Be<B<C<O<N<F<Ne
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Li<Be<B<C<N<O<F<Ne
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Li<B<Be<C<O<N<F<Ne
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Li<B<Be<C<N<O<F<Ne

Read the following statements (S) and Explanation (E). Choose the correct answers from the codes (1), (2), (3) and (4):

S : Sulphate is estimated as ${BaSO}_{4}$ and not as ${MgSO}_{4}$ .

E : Ionic radius of ${Mg}^{2 +}$ is smaller than ${Ba}^{2 +}$ .

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S is correct but E is wrong
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S is wrong but E is correct
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Both S and E are correct and E is correct explanation of S
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Both S and E are correct but E is not correct explanation of S

The incorrect order of electronegativity is :

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Cl > S > P > Si
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Si > Al > Mg > Na
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F > Cl > Br > I
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None of the above.

Element of the third period that is expected to exhibit positive electron gain enthalpy is:

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Na
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Al
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Cl
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Ar

The correct order of 3rd ionisation potential of Na, Mg, Al and Si is

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Si > Al > Mg > Na
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Mg > Si > Al > Na
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Mg > Na > Si > Al
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Mg > Na > Al > Si

Identify the wrong statement in the following:

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Amongst isoelectronic species, smaller the positive charge on the cation, smaller is the ionic radius
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Amongst isoelectronic species, greater the negative charge on the anion, larger is the ionic radius
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Atomic radius of the elements increases as one moves down the first group of the Periodic Table
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Atomic radius of the elements decreases as one moves across from left to right in the 2nd period of the Periodic Table

The ionisation energy will be maximum for the process:

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$B a \to B a^{2 +}$
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$B e \to B e^{2 +}$
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$C s \to C s^{+}$
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$L i \to L i^{+}$

The group of metals having positive value of electron gain enthalpy is :-

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Cr, Fe
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Mn, Zn
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Fe, Zn
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Cr, Mn

Percentage ionic character, if electronegativity value of X=2.1 & Y=3.0, is :-

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20
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30
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17
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23

The correctly matched option is:-

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O < N < F < Ne : Order of electron affinity
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${Fe}^{+ 3} > {Fe}^{+ 2} > {Fe}^{+}$ : Order of atomic radius
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O > C > B > N : Order of ionisation energy
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$O^{- 2} < O^{-} < O < O^{+}$ : Increasing order of Z_eff

Identify the incorrect match.

Name IUPAC Official Name

a. Unnilunium (i) Mendelevium

b. Unniltrium (ii) Lawrecium

c. Unnilhexium (iii) Seaborgium

d. Unununnium (iv) Darmstadtium

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(b), (ii)
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(c), (iii)
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(d), (iv)
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(a), (i)

The group of elements in which the differentiating electron enters the anti penultimate
shell of atoms are called

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p-block elements
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d-block elements
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s-block elements
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f-block elements

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Practice Chemistry Quiz Questions and Answers

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Practice Chemistry Quiz Questions and Answers

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