The complex that will exhibit maximum ionic conductivity in aqueous solution is : -

  •  K4[Fe(CN)6]

  •   [Co(NH3)6]Cl3

  •  [Cu(NH3)4]Cl2

  •   [Ni(CO)4]

FeSO4 solution mixed with (NH4)2SO4 solution in 1:1 molar ratio gives the test of Fe2+ ion

but CuSO4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion because-

  • The former is an example of a basic compound, while the latter is an amphoteric compound

  • The former is an example of an amphoteric compound, while the latter is a basic compound

  • The former is an example of a double salt, while the latter is a coordination compound

  • The former is an example of a coordination compound, while the latter is a double salt

The oxidation number and coordination number of Co in [Co(H2O)(CN)(en)2]2+respectively are -     

  • ) 3, 6

  • ) 3, 2

  • ) 2, 2

  • ) 1, 3

The number of optical isomers shown by [Pt(NH3)(Br)(Cl)(py)] is -

  • 3

  • 2

  • 1

  • 0

The difference between a weak field ligand and a strong field ligand is-

  • Weak field ligands cause higher splitting in the d orbitals than strong field ligands.

  • Weak field ligands cause lower splitting in the d orbitals than strong field ligands.

  • Strong field ligands did not form a complex with metal ion.

  • None of the above.

Crystal field splitting energy is 

  • The heat of formation between the two levels (eg and t2g)

  • The combined pairing energy of the two levels (eg and t2g

  • The combined energy of the two levels (eg and t2g

  • The energy difference between the two levels (eg and t2g

[Cr(NH3)6]3+ is paramagnetic while Ni(CN)42- is diamagnetic because -

  • Electrons in the 3d orbitals remain unpaired in Ni(CN)42-

  • Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+

  • Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+

  • Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

A solution of [Ni(H2O)6]2+ is green but a solution of [Ni(CN)4]2– is colorless because -

  • There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2–

  • There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2–

  • There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2–

  • None of the above.

[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because -

  • Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

  • Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

  • Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

  • Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

The nature of bonding in metal carbonyls is -

  • The metal-carbon bonds in metal carbonyls have both σ and π characters.

  • The metal-carbon bonds in metal carbonyls have only σ character.

  • The metal-carbon bonds in metal carbonyls have only π character.

  • The metal-carbon bonds in metal carbonyls have only hydrogen bonding.

The greater value of the stability constant of complex salt indicates   -

  • The greater proportion of products.

  • The greater proportion of reactants

  • Lesser concentration of catalyst at equilibrium

  • 4 . All of the above

The correct order for the wavelengths of absorption in the visible region for the following is:

[Ni(NO2)6]4-, [Ni(NH3)6]2+[Ni(H2O)6]2+

  •  [Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-

  •  [Ni(H2O)6]2+ > [Ni(NH3)6]2+ > [Ni(NO2)6]4-

  •  [Ni(NH3)6]2+ > [Ni(H2O)6]2+ [Ni(NO2)6]4-

  •   [Ni(H2O)6]2+ [Ni(NO2)6]4- [Ni(NH3)6]2+

The number of unpaired electrons in the following complexes respectively are-

K4[Mn(CN)6], Fe(H2O)6]2+, K2[MnCl4]

  • 1, 4, 5

  • 2, 4, 5

  • 0, 3, 4

  • 2, 3, 4

a. Primary valencies are satisfied by negative ions while secondary valences are satisfied by negative ion only. 

b. A metal ion has a definite number of secondary valences around the central atom. 

c. Primary valences are usually ionizable, while secondary valences are non-ionizable

The correct statements among the above are -

 

  • a, b

  • a, c

  • b, c

  • a, b, c 

Match the following.

Ligand NameType of ligand
i. NO2-a. Hexadenate
ii. OH-b. Didentate
iii. C2O42-c. Monodentate
iv. EDTAd. Ambidentate ligand
  • i=d, ii=c, iii=b, iv=a

  •  i=c, ii=d, iii=b, iv=a

  •  i=c, ii=d, iii=a, iv=b

  • i=a, ii=c, iii=b, iv=d

The correct representation of tetrahydroxidozincate(II) is : 
 1. Zn(OH)42-2. Zn(OH)41-3.  Zn(OH)43-4.  Zn(OH)4

  • 1
  • 2
  • 3
  • 4

The correct representation of Potassium tris(oxalato)chromate(III) is-

1. K2Cr(C2O4)32. K3Cr(C2O4)33. K3Cr(C2O4)24. K2Cr(C2O4)4

 

  • 1
  • 2
  • 3
  • 4

The correct representation of pentaamminenitrito-O-cobalt(III) is

1. Co(NH3)5(ONO)3+2.  Co(NH3)5(ONO)2+3. Co(NH3)5(ONO)2-4.  Co(NH3)5(ONO)3-

 

  • 1
  • 2
  • 3
  • 4

The correct representation of potassium tetracyanidonickelate(II) is

1. K3Ni(CN)42. KNi(CN)43. K2Ni(CN)44. K2Ni(CN)5

 

 

  • 1
  • 2
  • 3
  • 4

The correct splitting diagram of d orbitals in an octahedral crystal field is

  •  

  • None of the above.

The ligand(s)that show a chelating effect is/are-

 

 

  • Diethylenetriamine

  • Oxalato

  • Both 1 and 2

  • None of the above.

The incorrect statement(s) among the following options is/are:

 

  • Cis- Platin is a coordination compound of Platinum.

  • Gold is extracted by the addition of zinc metal. 

  • None of the above.

  • Chlorophyll is a coordination compound of magnesium. 

 Optical isomerism is shown by

  •  [Cr(ox)3]3+

  •  [PtCl2(en)2]2+

  •  [Cr(NH3)2Cl2en]+

  • All of the above.

The incorrect statement(s) among the following option is/are-

  • In a coordination entity, the central atom or ion is surrounded by a suitable number of neutral molecules or negative ions ( called ligands). 

  • Coordination number is also referred as ligancy.

  •  Coordination polyhedrons is the spatial arrangement of the ligands that are directly attached to the central metal ion in the coordination sphere.

  • None of these.

The correct statement(s) among the following options is/are :

  • Complexes in which the metal ion is bound to only one kind of a donor group are homoleptic complexes.

  •  Heteroleptic complexes are those complexes where the central metal ion is bound to only one type of donor group.

  •  [Pt(Cl)4]2- is an example of a homoleptic complex.

  • Both (1) and (3) 

Ethylene diaminetetraacetate (EDTA) ion is :

  • Bidentate ligand with two "N" donor atoms

  • Tridentate ligand with three "N" donor

  • Hexadentate ligand with four "O" and two atoms "N'' donor atoms

  • Unidentate ligand

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