The complex that will exhibit maximum ionic conductivity in aqueous solution is : -
K4[Fe(CN)6]
[Co(NH3)6]Cl3
[Cu(NH3)4]Cl2
[Ni(CO)4]
FeSO4 solution mixed with (NH4)2SO4 solution in 1:1 molar ratio gives the test of Fe2+ ion
but CuSO4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion because-
The former is an example of a basic compound, while the latter is an amphoteric compound
The former is an example of an amphoteric compound, while the latter is a basic compound
The former is an example of a double salt, while the latter is a coordination compound
The former is an example of a coordination compound, while the latter is a double salt
The oxidation number and coordination number of Co in [Co(H2O)(CN)(en)2]2+respectively are -
) 3, 6
) 3, 2
) 2, 2
) 1, 3
The number of optical isomers shown by [Pt(NH3)(Br)(Cl)(py)] is -
3
2
1
0
The difference between a weak field ligand and a strong field ligand is-
Weak field ligands cause higher splitting in the d orbitals than strong field ligands.
Weak field ligands cause lower splitting in the d orbitals than strong field ligands.
Strong field ligands did not form a complex with metal ion.
None of the above.
Crystal field splitting energy is
The heat of formation between the two levels (eg and t2g)
The combined pairing energy of the two levels (eg and t2g)
The combined energy of the two levels (eg and t2g)
The energy difference between the two levels (eg and t2g)
[Cr(NH3)6]3+ is paramagnetic while Ni(CN)42- is diamagnetic because -
Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
Electrons in the 3p orbitals remain unpaired in Ni(CN)42-
A solution of [Ni(H2O)6]2+ is green but a solution of [Ni(CN)4]2– is colorless because -
There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2–
There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2–
There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2–
[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because -
Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
The nature of bonding in metal carbonyls is -
The metal-carbon bonds in metal carbonyls have both σ and π characters.
The metal-carbon bonds in metal carbonyls have only σ character.
The metal-carbon bonds in metal carbonyls have only π character.
The metal-carbon bonds in metal carbonyls have only hydrogen bonding.
The greater value of the stability constant of complex salt indicates -
The greater proportion of products.
The greater proportion of reactants
Lesser concentration of catalyst at equilibrium
4 . All of the above
The correct order for the wavelengths of absorption in the visible region for the following is:
[Ni(NO2)6]4-, [Ni(NH3)6]2+, [Ni(H2O)6]2+
[Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-
[Ni(H2O)6]2+ > [Ni(NH3)6]2+ > [Ni(NO2)6]4-
[Ni(NH3)6]2+ > [Ni(H2O)6]2+ > [Ni(NO2)6]4-
[Ni(H2O)6]2+ > [Ni(NO2)6]4- > [Ni(NH3)6]2+
The number of unpaired electrons in the following complexes respectively are-
K4[Mn(CN)6], Fe(H2O)6]2+, K2[MnCl4]
1, 4, 5
2, 4, 5
0, 3, 4
2, 3, 4
a. Primary valencies are satisfied by negative ions while secondary valences are satisfied by negative ion only.
b. A metal ion has a definite number of secondary valences around the central atom.
c. Primary valences are usually ionizable, while secondary valences are non-ionizable
The correct statements among the above are -
a, b
a, c
b, c
a, b, c
Match the following.
i=d, ii=c, iii=b, iv=a
i=c, ii=d, iii=b, iv=a
i=c, ii=d, iii=a, iv=b
i=a, ii=c, iii=b, iv=d
The correct representation of tetrahydroxidozincate(II) is : 1. Zn(OH)42-2. Zn(OH)41-3. Zn(OH)43-4. Zn(OH)4
The correct representation of Potassium tris(oxalato)chromate(III) is-
1. K2Cr(C2O4)32. K3Cr(C2O4)33. K3Cr(C2O4)24. K2Cr(C2O4)4
The correct representation of pentaamminenitrito-O-cobalt(III) is
1. Co(NH3)5(ONO)3+2. Co(NH3)5(ONO)2+3. Co(NH3)5(ONO)2-4. Co(NH3)5(ONO)3-
The correct representation of potassium tetracyanidonickelate(II) is
1. K3Ni(CN)42. KNi(CN)43. K2Ni(CN)44. K2Ni(CN)5
The correct splitting diagram of d orbitals in an octahedral crystal field is
The ligand(s)that show a chelating effect is/are-
Diethylenetriamine
Oxalato
Both 1 and 2
The incorrect statement(s) among the following options is/are:
Cis- Platin is a coordination compound of Platinum.
Gold is extracted by the addition of zinc metal.
Chlorophyll is a coordination compound of magnesium.
Optical isomerism is shown by
[Cr(ox)3]3+
[PtCl2(en)2]2+
[Cr(NH3)2Cl2en]+
All of the above.
The incorrect statement(s) among the following option is/are-
In a coordination entity, the central atom or ion is surrounded by a suitable number of neutral molecules or negative ions ( called ligands).
Coordination number is also referred as ligancy.
Coordination polyhedrons is the spatial arrangement of the ligands that are directly attached to the central metal ion in the coordination sphere.
None of these.
The correct statement(s) among the following options is/are :
Complexes in which the metal ion is bound to only one kind of a donor group are homoleptic complexes.
Heteroleptic complexes are those complexes where the central metal ion is bound to only one type of donor group.
[Pt(Cl)4]2- is an example of a homoleptic complex.
Both (1) and (3)
Ethylene diaminetetraacetate (EDTA) ion is :
Bidentate ligand with two "N" donor atoms
Tridentate ligand with three "N" donor
Hexadentate ligand with four "O" and two atoms "N'' donor atoms
Unidentate ligand
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