For M 2+ /M, and M 3+ /M 2+ , the E ° values of some metals are given in the table below: Cr +2 /Cr = -0.9 V Cr +3 /Cr +2 = -0.4V Mn +2 /Mn = -1.2V Mn +3 /Mn +2 = +1.5 V Fe +2 /Fe = -0.4V Fe +3 /Fe +2 = +0.8 V The correct inference(s) from the above data is/are:

T he increasing order of their stability is Mn + 3 < Fe + 3 < Cr + 3

T he increasing order of above-mentioned metals' ability to get oxidized is: Fe < Cr < Mn

T he increasing order of above-mentioned metals' ability to get oxidized is: Fe > Cr > Mn

Chemistry - D F Block Elements - Quiz-7

The correct value of spin only magnetic moment value of $C r^{3 +}$ ion is -

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2.87 BM
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3.87 BM
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3.47 BM
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3.57 BM

The incorrect statement among the following is:

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Copper liberates hydrogen from acids.
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In its higher oxidation states, manganese forms stable compounds with oxygen and fluorine.
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Mn³⁺, and Co³⁺ are oxidizing agents in an aqueous solution.
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${Ti}^{2 +}, and {Cr}^{2 +}$ are reducing agents in an aqueous solution.

The reason for the highest oxidation state of manganese in fluoride is +4 (Mn $F_{4}$ ) but the highest oxidation state in oxides is +7 ( ${Mn}_{2} O_{7}$ ) :

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Fluorine is more electronegative than oxygen.
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Fluorine does not possess d orbitals.
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Fluorine stabilizes the lower oxidation state.
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In covalent compounds, fluorine can form a single bond only while oxygen forms a double bond.

HCl is not used to make the medium acidic in oxidation reactions of ${KMnO}_{4}$ , because-

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Both HCl and ${KMnO}_{4}$ act as oxidising agents.
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${KMnO}_{4}$ oxidises HCl into Cl₂, which is also an oxidising agent.
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${KMnO}_{4}$ is a weaker oxidising agent than HCl.
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${KMnO}_{4}$ acts as a reducing agent in the presence of HCl.

Compound that cannot act as oxidizing agents is -

$1 . {CrO}_{3} 2 . {CrO}_{4}^{2 -} 3 . {WO}_{3} 4 . Both 1 and 2$

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1
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2
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3
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4

Match the properties given in Column I with the metals given in Column II

Column I - (Property)	Column II - (Metal)
A. Element with highest second ionisation enthalpy	1. V
B. Element with highest third ionisation enthalpy	2. Cr
C. M in M(CO $)_{6}$ is	3. Cu
D. Element with the highest heat of atomisation	4. Zn

The correct match is :

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A-3, B-4, C-1, D-2
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A-3, B-4, C-2, D-1
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A-1, B-2, C-4, D-3
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A-3, B-2, C-4, D-1

Most common oxidation state of cerium (Ce) is :

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+2, +3
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+2, +4
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+3, +4
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+3, +5

The correct order of decreasing second ionization enthalpy of Ti(22), V(23), Cr (24) and Mn(25) is :

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Cr > Mn > V > Ti
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V > Mn > Cr > Ti
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Mn > Cr > Ti > V
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Ti > V > Cr > Mn

Electronic configuration of a transition element X in +3 oxidation state is [Ar] 3d⁵. What is its atomic number?

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25
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26
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27
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24

The correct statement among the following is-

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Cu(II)_aq is more stable.
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Cu(II)_aq is less stable.
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Cu(I) and Cu(II) are equally stable.
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Stability of Cu(I) and Cu(II) depends on nature of copper salts.

The number of 3d electrons in each of the Cr³⁺ ion is-

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5
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6
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3
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7

Metallic radii of some transition elements are given below. An element that have highest density is -

Element	Fe	Co	Ni	Cu
Metallic radii/pm	126	125	125	128

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Fe
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Ni
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Co
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Cu

A compound that has coloure in solid state is -

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Ag₂SO₄
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CuF₂
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ZnF₂
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Cu₂Cl₂

On addition of small amount of KMnO₄, to concentrated H₂SO₄, a green oily compound is obtained which is highly explosive in nature. What is the compound ?
$1 . {Mn}_{2} O_{7} 2 . {MnO}_{2} 3 . {MnSO}_{4} 4 . {Mn}_{2} O_{3}$

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1
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2
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3
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4

The magnetic nature of elements depends on the presence of unpaired electrons. Which of the configuration of transition element will shows highest magnetic moment ?

$1 . 3 d^{7}$

$2 . 3 d^{5}$

$3 . 3 d^{8}$

$4 . 3 d^{2}$

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1
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2
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3
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4

There are 14 elements in actinoid series. Which of the following elements does not belong to this series?

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U
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Np
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Tm
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Fm

The electronic configuration of gadolinium (Atomic number of 64) is :

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$[Xe] 4 f^{3} 5 d^{5} 6 s^{2}$
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$[Xe] 4 f^{7} 5 d^{2} 6 s^{1}$
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$[Xe] 4 f^{7} 5 d^{1} 6 s^{2}$
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$[Xe] 4 f^{8} 5 d^{6} 6 s^{2}$

Actinoids that can show oxidation states up to +7 is -

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Am
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Th
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U
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Np

An actinoid that does not have one electron in its 6d orbital is -

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U (Atomic number. 92)
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Np (Atomic number. 93)
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Pu (Atomic number. 94)
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Cm (Atomic number. 96)

The highest spin-only magnetic moment value among the following is -

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${Ti}^{3 +}$
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${Mn}^{2 +}$
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${Fe}^{2 +}$
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${Co}^{3 +}$

Match the catalysts given in Column I with the processes given in Column II.

Column I - (Catalyst)	Column II - (Process)
A. Ni in the presence of hydrogen	1. Contact process
B. $C u_{2} C l_{2}$	2. Vegetable oil to ghee
C. $V_{2} O_{5}$	3. Sandmeyer reaction
D. Finely divided iron	4. Haber's process
	5. Decomposition of $K C l O_{3}$

Codes

A B C D

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2. 2 3 1 4
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1. 3 4 2 5
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4. 4 5 3 2
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3. 5 4 3 2

Match the properties given in Column I with uses given in Column II

Column I - (Property)	Column II - (Metal)
A. An element that can show +8 oxidation state	1. Mn
B. 3d block element that can show up to +7	2. Cr 3. Os
C. 3d block element with the highest melting point

Codes

A B C

2. 1 2 3

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3. 1 4 3
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4. 4 2 3
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1. 3 1 2
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4. Fe

The correct statement regarding Ag is -

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It is a hard metal.
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It is not a transition element.
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It has a partially filled d orbital in +2 oxidation state. Thus, it is a transition element.
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None of the above

The enthalpy of atomization of transition metals is high due to -

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High effective nuclear charge
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A large number of valence electrons
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Very strong metallic bonds
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All of the above

The transition metals generally form coloured compounds due to -

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Absorption of radiation to promote an electron .
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Presence of ligands, the d-orbitals split up into two sets of orbitals.
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Energy required to promote an electron in d subshell is low.
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All of the above.

For M²⁺/M, and M³⁺/M²⁺, the $E °$ values of some metals are given in the table below:

Cr⁺²/Cr = -0.9 V	Cr⁺³/Cr⁺² = -0.4V
Mn⁺²/Mn = -1.2V	Mn⁺³/Mn⁺²= +1.5 V
Fe⁺²/Fe = -0.4V	Fe⁺³/Fe⁺² = +0.8 V

The correct inference(s) from the above data is/are:

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The increasing order of their stability is ${Mn}^{+ 3} < {Fe}^{+ 3} < {Cr}^{+ 3}$
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The increasing order of above-mentioned metals' ability to get oxidized is: Fe < Cr < Mn
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The increasing order of above-mentioned metals' ability to get oxidized is: Fe > Cr > Mn
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Both (1) and (2)

Incorrect statement(s) regarding inner transition elements is/are:

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Lanthanoid contraction has a stronger impact on the radius than actinoid contraction
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Lanthanoids commonly show +4 oxidation state
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Actinoids are more reactive metals than lanthanoids.
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Both (1) and (2)

Match the solutions given in Column I and the colours are given in Column II.

Column I - (Aqueous solution of salt)	Column II - (Colour)
A. ${FeSO}_{4} . 7 H_{2} O$	1. Green
B. ${NiCl}_{2} . 4 H_{2} O$	2. Light pink
C. ${MnCl}_{2} . 4 H_{2} O$	3. Blue
D. ${CoCl}_{2} . 6 H_{2} O$	4. Pale green
	5. Pink

Codes

A B C D

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4. 4 1 2 5
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2. 1 2 3 5
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3. 5 4 3 2
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1. 2 3 4 1

The catalytic activity of transition metals and their compounds is ascribed mainly to:

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their unfilled d-orbitals
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their ability of adopt variable oxidation states
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their chemical reactivity
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their magnetic behaviour

Which one of the following does not correctly represent the correct order of the property indicated against it ?

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$T i^{3 +} < V^{3 +} < C r^{3 +} < M n^{3 +}$ : increasing magnetic moment
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$T i < V < C r < M n$ : increasing melting point
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Ti < V < Mn < Cr : increasing 2nd ionization enthalpy
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Ti < V < Cr < Mn : increasing number of oxidation states

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Practice Chemistry Quiz Questions and Answers

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Practice Chemistry Quiz Questions and Answers

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