A set of ions among the following has 3d 2 electronic configuration is:-

Ti 2 + , V 3 + , Cr 4 + , Mn 5 +

Ti 4 + , V 3 + , Cr 2 + , Mn 3 +

Ti 3 + , V 2 + , Cr 3 + , Mn 4 +

Zn gives H 2 gas with H 2 SO 4 , and HCl but not with HNO 3 because:-

NO 3 Θ is reduced in preference to hydronium ion.

Zn acts as an oxidizing agent when react with HNO 3

HNO 3 is weaker acid than H 2 SO 4 , and HCl

In electrochemical series Zn is above hydrogen

Mn 2+ compounds are more stable than Fe 2+ compounds towards oxidation in their +3 state because -

3d 5 configuration is more stable than 3d 6 configuration.

3d 6 configuration is more stable than 3d 5 configuration.

3p 5 configuration is less stable than 3p 6 configuration.

3p 6 configuration is less stable than 3p 5 configuration.

Chemistry - D F Block Elements - Quiz-8

The most common oxidation state of lanthanoid is -

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2
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5
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3
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4

Which of the following exhibits only a +3 oxidation state?

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Th
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Ac
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Pa
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U

Four successive members of the first series of the transition metals are listed below. For which one of them does the standard potential $(E °_{M^{2 +} / M})$ value have a positive sign?

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Ni (Z = 28)
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Cu (Z = 29)
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Fe (Z = 26)
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Co (Z = 27)

Colourless ion among the following is:

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Cr⁺⁴
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Sc⁺³
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Ti⁺³
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V⁺³

An element among the following that exhibit maximum oxidation state is :

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Cr
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Mn
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Fe
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V

Ion that gives color with the water :

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$C u^{+}$
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$C r^{3 +}$
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$N a^{+}$
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None of the above.

Maximum oxidation state is shown by :

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La
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Gd
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Eu
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Am

A coloured, and paramagnetic compound among the following is -

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$C u F_{2}$
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$K_{2} C r_{2} O_{7}$
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$K M n O_{4}$
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$K_{4} [F e {(C N)}_{6}]$

Compound 'A' in acidic medium does not give ppt with $H_{2} S$ but in $N H_{4} O H$ medium gives a ppt comp. 'A' is :

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$F e C l_{3}$
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$A l C l_{3}$
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$Z n C l_{2}$
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$S n C l_{2}$

An element among the following that can form more than one binary compound with chlorine is:-

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Zn
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K
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Ca
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Fe

$FeCr_{2}O_{4} $ reacts with $N a_{2} C O_{3}$ gives the product :

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FeO
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$N a_{2} C r O_{4}$
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$N a_{2} C r_{2} O_{7}$
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$F e_{3} O_{4}$

A set of ions among the following has 3d² electronic configuration is:-

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${Ti}^{+}, V^{4 +}, {Cr}^{6 +}, {Mn}^{7 +}$
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${Ti}^{4 +}, V^{3 +}, {Cr}^{2 +}, {Mn}^{3 +}$
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${Ti}^{2 +}, V^{3 +}, {Cr}^{4 +}, {Mn}^{5 +}$
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${Ti}^{3 +}, V^{2 +}, {Cr}^{3 +}, {Mn}^{4 +}$

General electronic configuration of lanthanoids is :

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(n – 2) f ^1–14 (n – 1) s² p⁶ d^0–1 ns²
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(n – 2) f ^10–14 (n – 1) d^0–1 ns²
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(n – 2) f ^0–14(n – 1) d¹⁰ ns²
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(n – 2) d^0–1 (n – 1) f ^1–14 ns²

Zn gives H₂ gas with H₂SO₄, and HCl but not with HNO₃ because:-

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Zn acts as an oxidizing agent when react with HNO₃
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HNO₃ is weaker acid than H₂SO₄, and HCl
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In electrochemical series Zn is above hydrogen
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NO₃^Θ is reduced in preference to hydronium ion.

Incorrect statement among the following options is :

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$L a {(O H)}_{3}$ is less basic than $L u {(O H)}_{3}$
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In Lanthanide series ionic radius of $L n^{+ 3}$ ions decreases.
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La is actually an element of transition series rather Lanthanide.
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Atomic radius of Zr and Hf are same because of Lanthanide contraction.

The catalytic activity of transition metals is due to :

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High enthalpy of atomization
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Paramagnetic behaviour
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Colour of hydrated ions
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Variable oxidation states

The basic character of the transition metal monoxides follows the order :

(Atomic nos. Ti = 22, V = 23, Cr = 24, Fe = 26)

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VO > CrO > TiO > FeO
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CrO > VO > FeO > TiO
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TiO > FeO > VO > CrO
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TiO > VO > CrO > FeO

The correct order of ionic radii of Y³⁺, La³⁺, Eu³⁺, and Lu³⁺ is : -

Atomic nos. Y = 39, La = 57, Eu = 63, Lu = 71.

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Y³⁺ < La³⁺ < Eu³⁺ < Lu³⁺
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Y³⁺ < Lu³⁺ < Eu³⁺ < La³⁺
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Lu³⁺ < Eu³⁺ < La³⁺ < Y³⁺
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La³⁺ < Eu³⁺ < Lu³⁺< Y³⁺

Mn²⁺ compounds are more stable than Fe²⁺ compounds towards oxidation in their +3 state because -

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3d⁵ configuration is more stable than 3d⁶ configuration.
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3d⁶ configuration is more stable than 3d⁵ configuration.
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3p⁵ configuration is less stable than 3p⁶ configuration.
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3p⁶ configuration is less stable than 3p⁵ configuration.

+2 oxidation state becomes more stable in the first half of the first-row transition elements with increasing atomic number because -

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s-orbital is becoming more and more half-filled.
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f-orbital is becoming more and more half-filled.
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d-orbital is becoming more and more half-filled.
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p-orbital is becoming more and more half-filled.

The oxo metal anions of 3d series in that the metal exhibits the oxidation state equal to its group number is /are -

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${VO}_{3}^{-}$
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${CrO}_{4}^{2 -}$
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${MnO}_{4}^{-}$
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All of the above.

The consequence(s) of lanthanoid contraction is/are :

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Similarity in the properties of the second and third transition series.
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Separation of lanthanoids is difficult.
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Variation in the basic strength of lanthanide hydroxides.
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All of the above.

The d-block elements that may not be regarded as the transition elements are -

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Mn, Fe, Ni because these have partially filled d-subshell.
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Mn, Fe, Ni because these have completely filled d-subshell.
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Zn, Cd, and Hg because these have completely filled d-subshell.
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Zn, Cd, and Hg because these have partially filled d-subshell.

The electronic configuration of the transition elements is -

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(n − 1)d^1-10 ns^0-2
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(n − 1)d^1-10 ns²
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nf² np^1-6
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nd² np^1-6

The different oxidation states exhibited by the lanthanoids are-

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+2, -3, +4
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-2, -3, -4
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+2, +3, -4
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+2, +3, +4

‘Disproportionation’ reaction indicates -

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A relatively less stable oxidation state undergoes an oxidation−reduction reaction.
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A relatively more stable oxidation state undergoes an oxidation−reduction reaction.
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A relatively less stable oxidation state undergoes a hydrogenation reaction.
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A relatively more stable oxidation state undergoes a hydrogenation reaction.

The number of unpaired electrons in the gaseous ions ${Mn}^{3 +}, {Cr}^{3 +}, V^{3 +,} and {Ti}^{3 +}$ are respectively -

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3, 2, 3, and 1
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2, 2, 3, and 1
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4, 3, 2, and 1
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1, 2, 3, and 4

Alloy that contains lanthanoid metals is-

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Mischmetal
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Permalloy
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Supermalloy
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Brass

The atomic numbers of the inner transition elements among the following

29, 59, 74, 95, 102, 104 are -

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29, 59, 74
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59, 95, 102
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95, 102, 104
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59, 74, 95

Match the following :

Elements	Electronic configuration
i. 61	a. $[Rn] 5 f^{13} 6 d^{0} 7 s^{2}$
ii. 91	b. $[Xe] 4 f^{5} 6 s^{2}$
iii. 101	c. $[Rn] 5 f^{14} 6 d^{7} 7 s^{2}$
iv. 109	d. $[Rn] 5 f^{2} 6 d^{1} 7 s^{2}$

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i=b, ii=d, iii=a, iv=c
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i=c, ii=a, iii=d, iv=b
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i=c, ii=a, iii=d, iv=b
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i=a, ii=c, iii=b, iv=d

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Practice Chemistry Quiz Questions and Answers

0:0:1

Practice Chemistry Quiz Questions and Answers

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