During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is
55 minutes
110 minutes
220 minutes
330 minutes
If the E°cell for a given reaction has a negative value, which of the following gives correct relationships for the values of ∆G° and Keq ?
∆G° >0; Keq< 1
∆G° >0; Keq>1
∆G° < 0; Keq> 1
∆G° <0; Keq< 1
The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60 x 10-19 C)
6 x 1020
3.75 x 1020
7.48 x 1023
6 x 1023
Zinc can be coated on iron to produce galvanised iron but the reverse is not possible. It is because
zinc is lighter than iron
zinc has lower melting point than iron
zinc has lower negative electrode potential than iron
zinc has higher negative electrode potential than iron
The pressure of H2 required to make the potential of H2-electrode zero in pure water at
298 K is
10-12 atm
10-10 atm
10-4 atm
10-14 atm
A device that converts energy of combustion of fuels like hydrogen and methane, directly
into electrical energy is known as
fuel cell
electrolytic cell
dynamo
Ni-Cd cell
The weight of silver (at. wt.= 108) displaced by a quantity of electricity which displaces 5600 mL of O2 at STP will be :
5.4g
10.8g
54.0g
108.0g
At 25° C molar conductance of 0.1 molar aqueous solution of ammonium hydroxide is
9.54 ohm1cm2mol-1 and at infinite dilution its molar conductance is 238 ohm1cm2mol-1.
The degree of ionisation of ammonium hydroxide at the same concentration and
temperature is
2.080%
20.800%
4.008%
40.800%
A button cell used in watches functions as following
Zn(s) + Ag2O(s) + H2O (l) ⇌2Ag(s) + Zn2+(aq) + 2OH-(aq)
If half cell potentials are
Zn2+aq + 2e- → Znx; Eo = -0.76VAg2Os + H2Ol + 2e- → 2Ags + 2OH-aq; Eo = 0.34V
The cell potential will be
0.84 V
1.34 V
1.10 V
0.42 V
Limiting molar conductivity of NH4OH (i.e Åm(NH4OH)) is equal to:-
Åm (NH4Cl)+Åm(NaCl)-Åm(NaOH)
Åm(NaOH)+Åm(NaCl)-Åm(NH4Cl)
Åm(NH4OH)+Åm(NH4Cl)-Åm(HCl)
Å(NH4Cl)+Å(NaOH)-Å(NaCl)
Kohlrausch's law states that at
finite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
infinite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte depending on the nature of the other ion of th electrolyte.
infinite dilution, each ion makes definite contribution to conductance of an electrolyte whatever be the nature of the other ion of the electrolyte.
infinite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
The efficiency of a fuel cell is given by:
(a) ∆H/∆G (b) ∆G/∆S(c) ∆G/∆H (d) ∆S/∆G
A hypothetical electrochemical cell is shown below A l A+ (xM)l l B+ (yM) l BThe Emf measured is +0.20 V.The cell reaction is:-
A+ + e- → A ; B+ + e- → B
the cell reaction cannot be predicted
A + B+ → A+ + B
The E° in the given diagram is,
0.5
0.6
0.7
0.8
At 298K the standard free energy of formation of H2O(l) is –237.20kJ/mole while that of its ionisation into H+ iion and hydroxyl ions is 80 kJ/mole, then the emf of the following cell at 298 K will be
H2(g,1 bar) | H+ (1M) || OH–(1M) | O2 (g, 1bar)
0.40 V
0.81 V
1.23 V
–0.40 V
Which of the following cell can produce more electric work.
pt,H2|NH4Cl||0.1MCH3COOH|H2,pt
pt,H2|0.1MHCl||0.1MNaOH|H2,pt
pt,H2|0.1MHCl||0.1MCH3COOK|H2,pt
pt,H2|0.1MCH3COOK||0.1MHCl|H2,pt
At what [Br-][CO32−] does the following cell have its reaction at equilibrium?
Ag(s) | Ag2CO3(s) | Na2CO3 (aq) || KBr(aq) | AgBr(s) | Ag(s)
KSP = 8 × 10–12 for Ag2CO3 and KSP = 4 × 10–13 for AgBr
1 × 10–7
2 × 10–7
3 × 10–7
4 × 10–7
It is observed that the voltage of a galvanic cell using the reaction M(s) + xH+ → Mx+ + x2 H2 varies linearly with the log of the square root of the hydrogen pressure and the cube root of the Mx+ concentration. The value of x is
2
3
4
5
Acetic acid has Ka = 1.8 × 10–5 while formic acid had Ka = 2.1 × 10–4. What would be the magnitude of the emf of the cell
Pt(H2) 0.1M acetic acid+0.1M sodium acetate0.1M formic acid+0.1M sodium formate Pt(H2) at 25°C
0.0315 volt
0.0629 volt
0.0455 volt
0.0545 volt
Consider the cell Ag(s)|AgBr(s)|Br–(aq)||AgCl(s)|Cl–(aq)|Ag(s) at 25°C. The solubility product constants of AgBr & AgCl are respectively 5 × 10–13 & 1 × 10–10. For what ratio of the concentrations of Br– & Cl–ions would the emf of the cell be zero ?
1 : 200
1 : 100
1 : 500
200 : 1
Calculate the useful work of the reaction Ag(s) + 1/2Cl2(g) → AgCl(s)
Given E°Cl2/Cl– = + 1.36 V, E°AgCl/Ag,Cl– = 0.22 V
If PCl2 = 1 atmand T = 298 K
110 kJ/mol
220 kJ/mol
55kJ/mol
1000 kJ/mol
Which of these ions Cu+, Co3+, Fe2+ is stable in aqueous medium.
Given :E°Cu2+/Cu+ = 0.15 volt ; E°Cu+/Cu = 0.53 V ;E°Co3+/Co2+ = 1.82 V ;
E°Fe3+/Fe2+ = 0.77 V ;E°Fe2+Fe = –0.44 V ;E°O2,H+/H2O = 1.23 V
Cu+, Co3+
Co3+
Cu+
Co3+, Cu+, Fe2+
Select the correct statement if –
E°Mg2+/Mg = –2.4V, E°Sn4+/Sn2+ = 0.1 V, E°MnO4–,H+/Mn2+ = 1.5 V, E° I2/I–= 0.5 V
Here,
MnO4–is the strongest Oxidizing Agent and Mg is the strongest Reducing Agent.
Sn4+ + 2I– → Sn2+ + I2 is a spontaneous reaction.
Mg2+ + Sn2+ → Mg + Sn4+ is a spontaneous reaction.
Weakest oxidizing agent is Sn4+ and weakest reducing agent is Mn2+.
The temperature coefficient of a standard Cd–cell is –5.0 × 10–5 Vk–1 whose emf at 25°C is 1.018 V. During the cell operation, the temperature will –
increase
decrease
either
remains constant
A cell Ag | Ag+ || Cu++ | Cu initially contains 2M Ag+ and 2M Cu++ ions. The charger in cell potential after the passage of 10 amp current for 4825 sec is:
–1.00738
–0.0038 V
–0.000738 V
none
For the cell (at 298 K)
Ag(s) | AgCl(s) | Cl–(aq) || AgNO3(aq) | Ag(s)
Which of the following is correct –
The cell emf will be zero when [Ag+]a = [Ag+]c ([Ag+] in anodic compartment = [Ag+] in cathodic compartment)
The amount of AgCl(s) precipitate in anodic compartment will decrease with the working of the cell.
The concentration of [Ag+] = constant, in anodic compartment during working of cell.
Ecell = E°Ag+ | Ag –E°Cl–|AgCl|Ag −0.0591log1[Cl−]a
Equivalent conductivity of Fe2(SO4)3is related to molar conductivity by the expression:
1. ∧eq = ∧m
∧eq = ∧m/3
∧eq = 3∧m
∧eq = ∧m/6
Assertion : In electrochemical cell, we cannot use KCI in the salt bridge if anodic or cathodic
compartment consists of Ag+ of Pb2+ ion.
Reason : Salt bridge is employed to maintain the electrical neutrality and to minimize the liquid-liquid
junction potential.
What will be the quantity of iron deposited by ferrous and ferric ion by 1F (Fe = 56)
14g, 9.3 g
28g, 18.6 g
56g, 37.2g
None of these
(D)The reaction for the cell,
Zn | Zn2+ (1.0 M) || Cd2+ (1.0 M) | Cd is-
(A) Cd →Cd2++ 2e-
(B) Zn2+→ Zn – 2e-
(C) Cd + Zn2+→ Cd2++ Zn
(D) Zn + Cd2+ →Cd + Zn2+
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