The number of dihalogen derivatives of propane is/are-

PCl₅ reacts with propanone, to give:

A compound that does not undergo S_N1 reaction with OH^- is -

In the following reaction

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{Br} \underset{2. {\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{1. \mathrm{Mg}, \mathrm{Ether}}{\to }}\mathrm{X},$

The product 'X' is -

(a) CH₃CH₂OH

(b) CH₃COCH₃

(c) 

(d) CH₃OH

Iodoform reaction is given by  -

Which of the following compounds undergoes nucleophilic substitution reaction most easily ?

Consider the reactions :

i. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Br}\stackrel{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}{\to }$

    ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CH}-{\mathrm{CH}}_2{\mathrm{OC}}_2{\mathrm{H}}_5+\mathrm{HBr}$

ii. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Br}\stackrel{{\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{O}}^{-}}{\to }$

     ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CH}-{\mathrm{CH}}_2{\mathrm{OC}}_2{\mathrm{H}}_5+{\mathrm{Br}}^{-}$

The mechanisms of reactions (i) and (ii) are respectively :

The –OH group of an alcohol or the carboxylic acid can be replaced by – Cl using : 

Chloropicrin is obtained by the reaction of : 

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}\stackrel{\mathrm{NaCN}}{\to }\mathrm{X}\stackrel{\mathrm{Ni}/{\mathrm{H}}_2}{\to }\mathrm{Y}\stackrel{\mathrm{Acetic} \mathrm{anhydride}}{\to }\mathrm{Z}$

Z in the above reaction sequence is :-

When CH₃CH₂CHCl₂ is treated with NaNH₂, the product formed is : -

obtained by chlorination of n-butane, will be : -

An organic compound A$\left(C_4{H}_{9}Cl\right)$ on reaction with Na/diethyl ether gives a hydrocarbon which on monochlorination gives only one chloro derivative then, A is : -

Wurtz reaction is not preferred for the preparation of alkanes containing an odd number of carbon atoms

because -

The correct order of increasing dipole moment is -

A hydrocarbon C₅H₁₀ does not react with chlorine in dark but gives a single monochloro compound C₅H₉Cl in bright sunlight. Hydrocarbon could be -

Ambident nucleophiles are -

Compounds that react faster in ${\mathrm{S}}_{\mathrm{N}}2$ reaction with OH ^- from each given pair respectively are - 
a. CH₃Br or CH₃I  
b. (CH₃)₃CCl or CH₃Cl

Out of ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{Cl} \mathrm{and} {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CHClC}}_6{\mathrm{H}}_5$,

the one that gets easily hydrolyzed by aqueous KOH is -

p-Dichlorobenzene has a higher melting point than those of o- and m-isomers because -

Primary alkyl halide ${\mathrm{C}}_4{\mathrm{H}}_9\mathrm{Br}$ (A) reacted with alcoholic KOH to give compound (B). Compound (B) is reacted with HBr to give (C) which is an isomer of (A). When (A) is reacted with sodium metal it gives compound (D), ${\mathrm{C}}_8{\mathrm{H}}_{18}$ which is different from the compound formed when n-butyl bromide is reacted with sodium. Compound (A) is -

The substrate used for the preparation of 1-iodobutane from HI in the presence of ZnCl₂ is -

The best substrate for the preparation of 1-iodobutane in the presence of NaI / dry acetone is -

The substrate used for the preparation of 1-Bromobutane in the presence of peroxide is-

The Correct IUPAC name of the above structure is-

IUPAC name of major product upon dehydrohalogenation of 1-bromo-1-methylcyclohexane with sodium ethoxide in ethanol is -

Dehydrohalogenation of 2-Chloro-2-methyl butane with sodium ethoxide

in ethanol produces a major product. IUPAC name of the product is -

 IUPAC name of major the product upon dehydrohalogenation of 2,2,3-Trimethyl-3-bromopentane with sodium ethoxide in ethanol is -

(CH₃)₃CCH₂CH(Br)C₆H₅  is -

CH₃CH₂CH(CH₃)CH(C₂H₅)Cl, is -