Acidified permanganate solution

Chemistry - Hydrocarbons - Quiz-11

A compound having the highest boiling point among the following is -

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Iso-octane
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n-Octane
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2,2,3,3-Tetramethyl butane
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n-Butane

$C - C - C \equiv C ⇋_{B}^{A} C - C \equiv C - C$

[A] and [B] in the above mentioned reaction are respectively -

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Alc. KOH and ${NaNH}_{2}$
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${NaNH}_{2}$ and Lindlar catalyst
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${NaNH}_{2}$ and alcoholic KOH
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Lindlar catalyst and ${NaNH}_{2}$

Benzene reacts with ${CH}_{3} COCl$ in the presence of anhydrous ${AlCl}_{3}$ to give

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$C_{6} H_{5} {CH}_{3}$
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$C_{6} H_{5} Cl$
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$C_{6} H_{5} O_{2} Cl$
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$C_{6} H_{5} {COCH}_{3}$

Acidic hydrogen present among the following compound is -

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Ethyne
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Ethene
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Benzene
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Ethane

What will be the Product in the following reaction?

Which of the following compounds is insoluble even in hot concentrated H₂SO₄?

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Aniline
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Benzene
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Ethylene
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Hexane

Anti-Markovnikov’s addition of HBr is not observed in-

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Propene
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But-1-ene
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But-2-ene
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Pent-2-ene

Baeyer's reagent is-

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Acidified permanganate solution
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Alkaline permanganate solution
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Neutral permanganate solution
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Aqueous bromine solution

Which of the following compound has highest boiling point ?

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n-pentane
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2-methyl butane
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2, 2-dimethyl propane
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n-hexane

Consider the following reaction,

The structure of the major reaction intermediate formed in the above reaction is-

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$H_{3} C - \underset{\underset{D}{|}}{C} H - \underset{\underset{{CH}_{3}}{|}}{C} H - \overset{\circ}{C} H_{2}$
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$H_{3} C - \underset{\underset{D}{|}}{C} H - \underset{\underset{{CH}_{3}}{|}}{\overset{\circ}{C}} - {CH}_{3}$
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$H_{3} C - \underset{\underset{D}{|}}{\overset{\circ}{C}} - \underset{\underset{{CH}_{3}}{|}}{CH} - {CH}_{3}$
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$H_{3} C - \underset{}{\overset{\circ}{C} H} - \underset{\underset{{CH}_{3}}{|}}{CH} - {CH}_{3}$

Propyne $\to_{H_{2} {so}_{4}}^{{HgSO}_{4}}$ A.

What is compound A?

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2-Propanol
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Propane
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Propene
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2-Propanone

1-Butyne and 2-Butyne can be differentiated by -

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Bromine, CCl₄
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H₂ , Lindlar catalyst
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Dilute H₂SO₄, HgSO₄
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Ammoniacal cuprous chloride

Which of the following Hydrocarbon has the highest octane number?

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Methane
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Ethane
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Iso-octane
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Triptane

In the presence of peroxide, hydrogen chloride and hydrogen fluoride do not undergo anti-Markovnikov's

addition reaction with alkenes because-

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Both are highly ionic
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One is oxidizing and the other is reducing
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One of the steps is endothermic in both the cases
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All the steps are exothermic in both cases

In the reaction sequence (A) will be

$\to_{A n h y . A l C l_{3}}^{H B r} [A]$

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1-Bromo-2-ethyl cyclopentane
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1-Bromo-1-methyl cyclopentane
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1-Bromo-5-methyl cyclopentane
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5-Bromo-1-methyl cyclopentane

The reaction of propene with HOCl proceeds via the addition of-

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H⁺ in the first step
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Cl⁺ in the first step
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OH^- in the first step
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Cl⁺ and OH^- in a single step

The compound among the following that gives propyne on hydrolysis is-

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${Al}_{4} C_{3}$
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${Mg}_{2} C_{3}$
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$B_{4} C$
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${La}_{4} C_{3}$

Hydrogenation of the above compound in the presence of poisoned palladium catalyst gives

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optically active compound
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an optically inactive compound
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a racemic mixture
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a diastereomeric mixture

The reaction of HBr with

${CH}_{3} - \overset{\overset{{CH}_{3}}{|}}{C} = {CH}_{2}$ in the presence of peroxide will give -

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${CH}_{3} \underset{\underset{{CH}_{3}}{|}}{C} {BrCH}_{3}$
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CH₃CH₂CH₂CH₂Br
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${CH}_{3} \overset{\overset{{CH}_{3}}{|}}{C} {HCH}_{2} Br$
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${CH}_{3} {CH}_{2} \overset{\overset{{CH}_{3}}{|}}{C} {HCH}_{3}$

The product formed on reaction of HBr with propene is-

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1-bromopropane
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2-bromopropane
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3-bromopropane
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no reaction occurs

An alkene among the following that reacts fastest with H₂ under catalytic conditions is -

Propyne and propene can be distinguished by ,

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conc. H₂SO₄
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Br₂ in CCl₄
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diluted H₂SO₄
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AgNO₃ in ammonia

The product(s) obtained via oxymercuration (HgSO₄ + H₂SO₄ ) of but-1-yne is -

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${CH}_{3} {CH}_{2} - \overset{\overset{O}{| |}}{C} - {CH}_{3}$
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CH₃CH₂ CH₂-CHO
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CH₃CH₂CHO + HCHO
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CH₃ CH₂COOH + HCOOH

Ethene and ethyne can be distinguished by:

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Br₂ water
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KMnO₄ solution
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Cuprous chloride solution
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All of the above

Which among of the following alkyne will give an aldehyde on hydroboration oxidation reaction?

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$CH \equiv CH$
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${CH}_{3} - {CH}_{2} - C \equiv C - H$
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${CH}_{3} - C \equiv C - H$
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All of these

Reductive ozonolysis of the alkene, ${CH}_{3} - CH = C = {CH}_{2}$ will give

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only ${CO}_{2}$
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only ${CH}_{2} O$
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only ${CH}_{3} - CHO$
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mixture of ${CH}_{3} CHO, HCHO and {CO}_{2}$

The reaction intermediate involved in the addition of HBr to propene in the absence of peroxides is:

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$H^{+}$
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$B r^{-}$
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H
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Br

If the relative reactivity of $1 °$ , $2 °$ and $3 °$ hydrogen's towards chlorination is 1:3.8:5. The percentages of $1 °$ monochlorinated product obtained from 2-methylbutane is-

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% of 1^omonochlorinated product = $41.7 %$
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% of $1 °$ monochlorinated product = 35.2 %
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% of $1 °$ monochlorinated product = 23.1 %
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% of $1 °$ monochlorinated product = 33.2 %

The type of radicals that can be formed as intermediates during monochlorination of 2-methylpropane is-

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Primary and tertiary radicals
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Two types of primary radicals
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Primary and secondary radicals
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Two types of tertiary radical

Chlorination of methane takes place by -

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Elimination
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$S_{N} 1$
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Free radical
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$S_{N} 2$

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Practice Chemistry Quiz Questions and Answers

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Practice Chemistry Quiz Questions and Answers

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