Chemistry - Hydrocarbons - Quiz-12

The products formed after ozonolysis of Pent-2-ene are -

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Ethanal, Methanal
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Ethanal, Propanal
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Ethanal, Butanal
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Ethanal, Ethanal

The reason behind higher boiling point of one isomer of Pent-2-ene is-

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Cis - less polar than trans
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Trans - more polar than cis
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Cis - more intermolecular forces
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Trans - more dipole-dipole interactions

Incorrect statement regarding aromaticity is-

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Compound should have a planar structure.
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1. Compound should have a planar structure.
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The total number of π–electrons present in the ring should be equal to (4n + 2) $π electron$ , where n = 0, 1, 2 … etc. This is known as Huckel’s rule.
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Compound should have a linear structure

Not an aromatic molecule is/are -

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All of the above

The catalyst used in the conversion of benzene into acetophenone is done -

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Anhydrous AlCl₃
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HNO₃
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HCl
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Heating

The effect of branching on an alkane

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Increases its boiling point
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Decreases its boiling point
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Doesn’t change its boiling point
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None of the above

The product obtained on the addition of HBr to propene in the absence and presence of benzoyl peroxide are respectively

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1-Bromopropane, 2-Bromopropane
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2-Bromopropane, 1-Bromopropane
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1-Bromopropanol, 2-Bromopropanone
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2-Bromopropanone, 1-Bromopropanol

Decreasing order of acidic behavior of benzene, n-hexane, and ethyne is -

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Hexane > Ethyne > Benzene
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Benzene > Hexane > Ethyne
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Ethyne > Benzene > Hexane
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Benzene > Ethyne > Hexene

Incorrect statement towards reactivity of benzene is

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It undergoes electrophilic substitution reactions very easily
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Nucleophiles are attracted by a benzene ring
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Benzene is a planar molecule
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It has 12 sigma bonds

$Ethyne \overset{?}{\to}$ $Benzene$

The reagent used in the above conversion is -

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Cr₂O₃
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Alc. KOH
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Red hot Fe
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NaNH₂/liq.NH₃

Out of the above alkenes, the ones that can give 2-methyl butane on hydrogenation are-

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a, b
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b, c
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a, c
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a, b, c

The correct order of decreasing reactivity of the following compounds:

Chlorobenzene, 2,4-Dinitrochlorobenzene, and p-Nitrochlorobenzene

with an electrophile (E⁺) is -

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Chlorobenzene > p–Nitrochlorobenzene > 2,4-Dinitrochlorobenzene
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p – Nitro chlorobenzene > 2, 4-Dinitrochlorobenzene > Chlorobenzene
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Chlorobenzene > 2, 4-Dinitrochlorobenzene > p-Nitrochlorobenzene
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2, 4-Dinitrochlorobenzene > Chlorobenzene > p-Nitrochlorobenzene

Match the hydrocarbons in Column I with the boiling points given in Column II.

A. n-pentane	1. 282.5 K
B. iso-pentane	2. 309 K
C. neo-pentane	3. 301 K

Codes

A B C

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2 3 1
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1 2 3
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2 1 3
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3 2 1

Match the reactions given in Column I with the reaction types in Column II.

Column I	Column II
A. ${CH}_{2} = {CH}_{2} + H_{2} O \overset{H^{+}}{\to} {CH}_{3} {CH}_{2} OH$	1. Hydrogenation
B. ${CH}_{2} = {CH}_{2} + H_{2} \overset{Pd}{\to} {CH}_{3} - {CH}_{3}$	2. Halogenation
C. ${CH}_{2} = {CH}_{2} + {Cl}_{2} \to Cl - {CH}_{2} - {CH}_{2} - Cl$	3. Polymerisation
D. $3 CH \equiv CH \to_{Heat}^{Cu tube} C_{6} H_{6}$	4. Hydration
	5. Condensation

Codes

A B C D

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2 3 4 1
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1 2 3 5
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5 4 3 2
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4 1 2 3

Assertion: Toluene on Friedel Crafts methylation gives o- and p- xylene.

Reason: $C H_{3}$ -group bonded to benzene ring increases electron density at o- and p- position.

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Both assertion and reason are true and the reason is the correct explanation of assertion.
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Both assertion and reason are true and the reason is not the correct explanation of assertion.
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Assertion is true but the reason is false.
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Assertion is false but the reason is true.

Assertion: Nitration of benzene with nitric acid requires the use of concentrated sulphuric acid.

Reason: The mixture of concentrated sulphuric acid and concentrated nitric acid produces the electrophile, ${NO}_{2}^{+}$ .

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Both assertion and reason are true and the reason is the correct explanation of assertion.
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Both assertion and reason are true and the reason is not the correct explanation of assertion.
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Assertion is true but the reason is false.
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Assertion is false but the reason is true.

Assertion: Among isomeric pentanes, 2,2-dimethylpropane has the highest boiling point.

Reason: Branching does not affect the boiling point.

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Assertion is false but the reason is true.
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Both assertion and reason are true and the reason is the correct explanation of assertion.
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Both assertion and reason are true and the reason is not the correct explanation of assertion.
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Both assertion and reason are not correct

Which of the following is a free radical substitution reaction ?

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Acetylene with HBr
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Benzene with Br₂/AlCl₃
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Methane with Br₂/hv
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Propene with HBr/(C₆H₅COO)₂

The reagent that can be used to distinguish between 1-butyne and 2-butyne is:

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HCl
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$O_{2}$
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$B r_{2}$
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$N a N H_{2}$

In which of the following. E1 elimination is most favorable?

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All of the above

In Friedal craft reaction Toluene can be prepared by :

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C₆H₆ + CH₃Cl
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C₆H₅Cl + CH₄
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C₆H₆ + CH₂Cl₂
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C₆H₆ + CH₃COCl

The reagent used to converts propene to 1-propanol is

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H₂O, H₂SO₄
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B₂H₆, H₂O₂, OH^–
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Hg(OAc)₂, NaBH₄/H₂O
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Aq. KOH

Which of the following is not the characteristic of arenes :

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More stability
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Resonance
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Delocalization of π electrons
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Electrophilic addition

2-Bromopentane reacts with ethanolic KOH gives main product :

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Cis-2-pentene
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Trans-2-pentene
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1-pentene
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None of the above

Phenyl acetylene reacts with dil. $H_{2} S O_{4}$ in presence of $H g S O_{4}$ gives :

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1
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2
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3
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4

Compound 'A' on chlorination gives compound 'B'. 'B' reacts with alc. KOH to give gas 'C' which decolorizes Baeyer reagent. Ozonolysis of compound 'C' gives only HCHO compound. Compound 'A' is

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$C_{2} H_{6}$
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$C_{2} H_{4}$
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$C_{4} H_{10}$
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$C_{2} H_{5} Cl$

Reaction of HBr with propene in the presence of peroxide gives :-

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3-bromo propane
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Allyl bromide
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n-propyl bromide
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Isopropyl bromide

Using anhydrous AlCl₃ as catalyst, which one of the following reactions produces ethylbenzene (PhEt) :-

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${CH}_{3} - CH = {CH}_{2} + C_{6} H_{6}$
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$H_{2} C = {CH}_{2} + C_{6} H_{6}$
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$H_{3} C - {CH}_{3} + C_{6} H_{6}$
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$H_{3} C - {CH}_{2} OH + C_{6} H_{6}$

The molecular formula of diphenyl methane, .
The number of structural isomers possible when one of the hydrogens is replaced by a chlorine atom is :-

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4
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8
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7
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6

On ozonolysis , the alkene that gives the following produt is :

$C H_{3} C H_{2} C H O a n d C H_{3} C C H_{3} | | O$

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$C H_{3} C H_{2} C H = C H C H_{2} C H_{3}$
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$C H_{3} C H_{2} C H = C H C H_{3}$
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$C H_{3} - C = C H C H_{3} | C H_{3}$

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Practice Chemistry Quiz Questions and Answers

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Practice Chemistry Quiz Questions and Answers

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