$\underset{\left(ii\right) C{H}_{3}Br}{\overset{\left(i\right) NaN{H}_2.N{H}_2}{\to }} \left(A\right) \underset{Lindiar catalyst}{\overset{H_2}{\to }} \left(B\right) ; Product \left(B\right) is :$

A compound that gives an optically inactive compound on treatment with H₂(2 moles)/ Pt is-

Compound (x) will be:

Which alkyne yields butanoic acid (CH₃CH₂CH₂CO₂H) as the only organic product on treatment with ozone followed by the hydrolysis?

The degree of unsaturation in compound (A) is -

Correct order of rate of EASR (electrophilic aromatic substitution) is : 

The compound that will react most readily with gaseous bromine has the formula-

Rank the following reactions A,B and C in order of increasing rate,
(A)
(B)

(C)

Identify the position where E.A.S. can take place.

The rate of nitration will be:

 + HO^- $\to$ (A);      Product (A) of the given reaction is:  

      (2 mole)       (4 mole)   (major)

Which of the following compounds is the slowest to react with nitrosonium ion (NO⁺)?

The final product in the above sequence of reactions is-

 $\stackrel{{\mathrm{AlCl}}_3}{\to }$

What is the major product of the above Friedel-Craft reaction?

 The strongest acid among the following is -

Product (C) is:-

The reaction of toluene with chlorine in the presence of light gives:

Product (B) in the above mentioned reaction is-

 Product (A) in the above mentioned reaction is-

,vant't-Hoff factor (i) for the reaction is:-

A non-aromatic compound among the following compounds is-

A compound among the following that gives maximum % of meta product on nitration

(using HNO₃/H₂SO₄) is -

The action of AlCl₃ in Friedel Craft's reaction is:

n-Butylbenzene on oxidation with hot alkaline KMnO₄ gives:-

The compound among the following that undergoes bromination of its aromatic ring

(electrophilic aromatic substitution) at the fastest rate is-

Consider the following sequence of reactions.

${\mathrm{C}}_6{\mathrm{H}}_6 + {\mathrm{CH}}_3\mathrm{CH}={\mathrm{CH}}_2\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{PO}}_4}{\to }}\mathrm{A}\underset{2.{\mathrm{H}}_3{\mathrm{O}}^{+}, \mathrm{heat}}{\overset{1.{\mathrm{O}}_2,\mathrm{Heat}}{\to }}\mathrm{B}+\mathrm{C}$

The products (B) and (C) are respectively-

Consider the following sequence of reactions.

$\underset{{\mathrm{NaHSO}}_3}{\overset{{\mathrm{OsO}}_4}{\to }}$A$\underset{2. \mathrm{NaOH}, \mathrm{heat}}{\overset{1. {\mathrm{HIO}}_4}{\to }}$B. The final product (B) is:

In the above compound, Cl will liberate easily in the form of-

The major product expected from the  mono-bromination of phenyl  benzoate is:

(A) C₈H₁₀ $\stackrel{{\mathrm{KMnO}}_4}{\to }$ (B)  C₈H₆O₄$\underset{\mathrm{Fe}}{\overset{{\mathrm{Br}}_2}{\to }}$  C₈H₅BrO₄  (C)  (one-product only)

The structure of A in the above-mentioned reaction is-