The correct statement among the following  regarding P4 molecule of white phosphorus is-

  • It has 6 lone pairs of electrons.

  • It has four P — P single bonds.

  • It has three P — P single bonds.

  • It has four lone pairs of electrons.

The correct statement among the following SO2 gas is -        

  • It acts as bleaching agent in moist conditions.

  • It's molecule has linear geometry.

  • It's concentrated solution is used as disinfectant.

  • It can be prepared by the reaction of dilute H2SO4 with metal sulphide.

The correct statement among the following is -

  • All the three N – O bond lengths in HNO3 are equal.

  • All P – Cl bond lenths in PCl5 molecule in gaseous state are equal.

  • P4 molecule in white phosphorus have angular strain therefore white phosphorus is very reactive.

  • PCl5 is ionic in solid state in which anion is tetrahedral and cation is octahedral.

The correct match among the following is -

  • As2O3 < SiO2 < P2O3 < SO2  - Basic strength.

  • AsH3 < PH3 < NH- Enthalpy of vaporisation.

  • S < O < Cl < F - More negative electron gain enthalpy

  • H2O > H2S > H2Se > H2Te -  Thermal stability 

a CaF2 + H2SO4  CaSO4 + 2HFb 2 HI + H2SO4  I2 + SO2 + 2H2Oc Cu + 2H2SO4  CuSO4 + SO2 + 2H2Od NaCl + H2SO4  NaHSO4 + HCl

Conc. H2SO4 is used as an oxidising reagent in above mentioned reaction is -

  • a and b

  • b and c

  • c and d

  • a and d

 Match the formulas of oxides given in Column I with the type of oxide given in Column II and mark the correct option.

Column I

Column II

A.  Pb3O4

B.  N2O

C.  Mn2O7

D.  Bi2O3

1. Neutral oxide

2. Acidic oxide

3. Basic oxide

4. Mixed oxide

Codes

        A            B            C            D

  •      1            2             3            4

  •      4            1             2            3

  •      3            2             4            1

  •       4            3             1            2

 Match the species given in Column I with the shape given in Column II and mark the correct option.

Column I

Column II

A. Its partial hydrolysis does not change oxidation state of central atom.

B. It is used in modern diving apparatus.

C. It is used to provide inert atmosphere for filling electrical bulbs.

D. It's central atom is in sp3dhybridisation.

1. He

2. XeF6

3. XeF4

4. Ar

Codes

         A            B            C            D

  •      1            4             2            3

  •      1            2             3            4

  •      2            1             4            3

  •       1            3             2            4

 The bonding present in nitrogen molecule is-

  • \(p\pi-d\pi\)
  • \(p\pi-p\pi\)
  • \(d\pi-d\pi\)
  • Only sigma bond

The correct statement about the reactivity of group 15 elements is 

  • Stability of their hydrides increases down the group.

  • Higher oxides are acidic in nature.

  • All elements form pentahalides.

  • They do not react with metals.

The element from group 15 that forms a strong bond with hydrogen is-

  • N
  • P
  • As
  • Sb

The condition that does not exist in the Haber process for manufacturing ammonia is-

  • Pressure (around 200 ×105 Pa)
  • Temperature (700 K)
  • Catalyst such as iron oxide
  • Presence of inert gases

Number of moles of copper used when

(i) Copper reacts with dilute nitric acid

(ii) Copper reacts with concentrated nitric acid

are respectively:-

  • 1,1

  • 1,3

  • 3,1

  • 3,3

An element that does not have d-orbital is-

  • P

  • N

  • As

  • Bi

The least basic compound is -

  • BiH3

  • AsH3

  • PH3

  • NH3

The incorrect statement about red phosphorus is-

  • It is hard and crystalline.

  • It is poisonous.

  • It is less reactive than white phosphorus.

  • It is insoluble in water.

The element that shows the highest catenation property is-

  • Phosphorus

  • Nitrogen

  • Antimony

  • Bismuth

The gas released on heating H3PO3 is 

  • Oxygen

  • Phosphine

  • Hydrogen

  • Water vapours

PClacts as -

  • Reducing agent

  • Oxidising agent

  • Dehydrating Agent

  • None of the above.

The electron gain enthalpy values for O → O and O →O2– are –141 and 702 kJ  mol-1 respectively.

The correct statement about the formation of oxides is-

  • Higher the electron gain enthalpy lower is lattice energy.

  • Higher the electron gain enthalpy higher is lattice energy.

  • Higher is the electron gain enthalpy higher is the stability of oxide.

  • O- is more stable than O2-

The group which contains the strongest oxidizing agent is-

  • Group 15

  • Group 16

  • Group 17

  • Group 18

 Halogen that forms only one oxoacid is

  • Chlorine

  • Fluorine

  • Bromine

  • Iodine

Xe + PtF6  ? 

The product of the above reaction is-

  • O2+[PtF6]-.

  • XeF4
  • XeF6
  • Xe+[PtF6]-

Phosphorous has the lowest oxidation state in :

  • H3PO3 

  • PCl3 

  • Ca3P2 

  • POF3

 A xenon fluoride that does not exist is -

1. XeF42. XeF23. XeF34. XeF6

  • 1
  • 2
  • 3
  • 4

(a) XeF+ 3H2O →

(b) XeF+ H2

The products formed in the above reactions respectively are -

1. XeO3 , XeOF42. XeO6 , XeOF43. XeO3 , XeOF64. XeO6 , XeOF6

  • 1
  • 2
  • 3
  • 4

Arrange the following in increasing order of acid strength.

HF, HCl, HBr, HI 

  • HCl < HBr < HI<HF  

  • HF < HCl < HI< HBr

  • HF < HCl < HBr < HI

  • HF< HBr < HI< HCl 

XeF4 is isostructural with -

  •  ICl4-       

  • IBr2-                   

  • BrO3-

  • ICl3-

The incorrect statement about noble gases is-

  • The atomic radii corresponds to van der Waal’s radii.

  • They have the largest size in a period.

  • They are also called inert gases.

  • They combine to form molecules.

In solid-state, PCl5 exist as -

  • Covalent solid.
  • Octahedral structure.
  • Ionic solid with PCl6+ octahedral and PCl4- tetrahedral.
  • Ionic solid with PCl4+ tetrahedral and PCl6- octahedral.

Match the items of Columns I and II and mark the correct option.

Column I Column II

A. H2SO4

B. CCl3NO2

C. Cl2

D. Sulphur

1. Highest electron affinity

2. Chalcogen

3. Tear gas

4. Storage batteries

Codes

          A           B             C           D

  •        4            3             1            2

  •        3            4             1            2

  •        4            1             2            3

  •        2            1             3            4

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