The correct statement among the following regarding P4 molecule of white phosphorus is-
It has 6 lone pairs of electrons.
It has four P — P single bonds.
It has three P — P single bonds.
It has four lone pairs of electrons.
The correct statement among the following SO2 gas is -
It acts as bleaching agent in moist conditions.
It's molecule has linear geometry.
It's concentrated solution is used as disinfectant.
It can be prepared by the reaction of dilute H2SO4 with metal sulphide.
The correct statement among the following is -
All the three N – O bond lengths in HNO3 are equal.
All P – Cl bond lenths in PCl5 molecule in gaseous state are equal.
P4 molecule in white phosphorus have angular strain therefore white phosphorus is very reactive.
PCl5 is ionic in solid state in which anion is tetrahedral and cation is octahedral.
The correct match among the following is -
As2O3 < SiO2 < P2O3 < SO2 - Basic strength.
AsH3 < PH3 < NH3 - Enthalpy of vaporisation.
S < O < Cl < F - More negative electron gain enthalpy
H2O > H2S > H2Se > H2Te - Thermal stability
a CaF2 + H2SO4 → CaSO4 + 2HFb 2 HI + H2SO4 → I2 + SO2 + 2H2Oc Cu + 2H2SO4 → CuSO4 + SO2 + 2H2Od NaCl + H2SO4 → NaHSO4 + HCl
Conc. H2SO4 is used as an oxidising reagent in above mentioned reaction is -
a and b
b and c
c and d
a and d
Match the formulas of oxides given in Column I with the type of oxide given in Column II and mark the correct option.
Column I
Column II
A. Pb3O4
B. N2O
C. Mn2O7
D. Bi2O3
1. Neutral oxide
2. Acidic oxide
3. Basic oxide
4. Mixed oxide
Codes
A B C D
1 2 3 4
4 1 2 3
3 2 4 1
4 3 1 2
Match the species given in Column I with the shape given in Column II and mark the correct option.
A. Its partial hydrolysis does not change oxidation state of central atom.
B. It is used in modern diving apparatus.
C. It is used to provide inert atmosphere for filling electrical bulbs.
D. It's central atom is in sp3d2 hybridisation.
1. He
2. XeF6
3. XeF4
4. Ar
1 4 2 3
2 1 4 3
1 3 2 4
The bonding present in nitrogen molecule is-
The correct statement about the reactivity of group 15 elements is
Stability of their hydrides increases down the group.
Higher oxides are acidic in nature.
All elements form pentahalides.
They do not react with metals.
The element from group 15 that forms a strong bond with hydrogen is-
The condition that does not exist in the Haber process for manufacturing ammonia is-
Number of moles of copper used when
(i) Copper reacts with dilute nitric acid
(ii) Copper reacts with concentrated nitric acid
are respectively:-
1,1
1,3
3,1
3,3
An element that does not have d-orbital is-
P
N
As
Bi
The least basic compound is -
BiH3
AsH3
PH3
NH3
The incorrect statement about red phosphorus is-
It is hard and crystalline.
It is poisonous.
It is less reactive than white phosphorus.
It is insoluble in water.
The element that shows the highest catenation property is-
Phosphorus
Nitrogen
Antimony
Bismuth
The gas released on heating H3PO3 is
Oxygen
Phosphine
Hydrogen
Water vapours
PCl5 acts as -
Reducing agent
Oxidising agent
Dehydrating Agent
None of the above.
The electron gain enthalpy values for O → O– and O →O2– are –141 and 702 kJ mol-1 respectively.
The correct statement about the formation of oxides is-
Higher the electron gain enthalpy lower is lattice energy.
Higher the electron gain enthalpy higher is lattice energy.
Higher is the electron gain enthalpy higher is the stability of oxide.
O- is more stable than O2-
The group which contains the strongest oxidizing agent is-
Group 15
Group 16
Group 17
Group 18
Halogen that forms only one oxoacid is
Chlorine
Fluorine
Bromine
Iodine
Xe + PtF6 →?
The product of the above reaction is-
O2+[PtF6]-.
Phosphorous has the lowest oxidation state in :
H3PO3
PCl3
Ca3P2
POF3
A xenon fluoride that does not exist is -
1. XeF42. XeF23. XeF34. XeF6
(a) XeF6 + 3H2O →
(b) XeF6 + H2O →
The products formed in the above reactions respectively are -
1. XeO3 , XeOF42. XeO6 , XeOF43. XeO3 , XeOF64. XeO6 , XeOF6
Arrange the following in increasing order of acid strength.
HF, HCl, HBr, HI
HCl < HBr < HI<HF
HF < HCl < HI< HBr
HF < HCl < HBr < HI
HF< HBr < HI< HCl
XeF4 is isostructural with -
ICl4-
IBr2-
BrO3-
ICl3-
The incorrect statement about noble gases is-
The atomic radii corresponds to van der Waal’s radii.
They have the largest size in a period.
They are also called inert gases.
They combine to form molecules.
In solid-state, PCl5 exist as -
Match the items of Columns I and II and mark the correct option.
A. H2SO4
B. CCl3NO2
C. Cl2
D. Sulphur
1. Highest electron affinity
2. Chalcogen
3. Tear gas
4. Storage batteries
3 4 1 2
2 1 3 4
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