PH₃ forms bubbles when passed slowly in water but NH₃ gets dissolves in water , because- 

All the five bonds of PCl₅ are not equivalent  because:

Nitrogen dioxide is paramagnetic in a gaseous state but diamagnetic in the solid, because -

The correct statement regarding bond angle of H₂O and H₂S is -

PCl₅ reacts with finely divided silver on heating and a white silver salt is obtained, which dissolves on adding excess aqueous NH₃ solution gives "A". Compond A is : 

Phosphorus forms a number of oxoacids. Out of these oxoacids, phosphinic acid has strong reducing property. its structure and reaction is 

An amorphous solid“A” burns in air to form a gas “B” which turns lime water milky. The gas is also produced as a by-product during roasting of sulphide ore.
This gas decolourises acidified aqueous KMnO₄, solution and reduces Fe³⁺ to Fe²⁺.The solid “A” and the gas “B” is -

On heating lead (II) nitrate gives a brown gas “A” The gas “A” on cooling changes to colourless solid “B”. Solid “B” on heating with NO changes to a blue solid ‘C’.

Identify ‘A’, ‘B’ and ‘C and also write reactions involved and draw the structures of ‘B’ and ‘C’.

On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treated with 3 moles of hydrogen (H₂) in the presence of a catalyst gives another gas (C) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Compounds (A) and (D) are :
 

Assertion: R₃P = O exists but R₃N = O does not (R = alkyl group).

Reason: Nitrogen doesn't have d orbitals.

Assertion: Nitrogen exists as a diatomic molecule and phosphorus as P₄.

Reason: Phosphorus is smaller in size, so it can form P₄.

Assertion (A) NaCl reacts with concentrated H₂SO₄ to give colourless fumes with a pungent smell. But on adding MnO₂ the fumes become greenish-yellow.

Reason (R) MnO₂ oxidizes HCl to chlorine gas which is greenish-yellow.

The disproportionation reaction of ${\mathrm{H}}_3{\mathrm{PO}}_3$ is as follows:

${\mathrm{H}}_3{\mathrm{PO}}_3 \stackrel{∆}{\to } \mathrm{X} + \mathrm{Y}$

X and Y in the above reaction sequence are-

Assertion: Phosphorous (V) has a tendency to only gain electrons as it is in its highest oxidation state.

Reason: PCl₅ can act as an oxidizing as well as a reducing agent.

The catalyst used in the contact process is -

The chemical formula of oleum is -

The correct order of bond dissociation energy of halogens ${\text{F}}_2, {\mathrm{Cl}}_2, {\mathrm{Br}}_2 \mathrm{and} {\mathrm{I}}_2$ is-

The correct sequence of increasing order of basic strength hydrides is -

_{$$\begin{gathered} 1. {\mathrm{BiH}}_3 \simeq {\mathrm{SbH}}_3 < {\mathrm{AsH}}_3 < {\mathrm{PH}}_3 < {\mathrm{NH}}_3 \\ 2. {\mathrm{BiH}}_3 > {\mathrm{NH}}_3 >\hspace{0.17em}{\mathrm{PH}}_3 > {\mathrm{SbH}}_3 > {\mathrm{AsH}}_3 \\ 3. {\mathrm{SbH}}_3 <\hspace{0.17em}{\mathrm{AsH}}_3 < {\mathrm{PH}}_3 < {\mathrm{NH}}_3 < {\mathrm{BiH}}_3 \\ 4. {\mathrm{AsH}}_3 > {\mathrm{NH}}_3 > {\mathrm{PH}}_3 > {\mathrm{SbH}}_3 > {\mathrm{BiH}}_3 \end{gathered}$$}

Lead nitrate upon heating gives-$$

An elements that does not show allotropy is -

The maximum covalency of nitrogen is -

The incorrect statement among the following is -

A brown ring is formed in the ring test for ${\mathrm{NO}}_3^{-}$ ion is due to the formation of -

Bismuth is present in +5 oxidation state in-

Ammonium dichromate and barium azide on heating gives : 

The number of  moles of NO produced by the oxidation of two moles of NH₃ will be -

The oxidation state of central atom in the anion of compound ${\mathrm{NaH}}_2{\mathrm{PO}}_2$ will be -

 A compound that does not have tetrahedral shape is -

Peroxoacids of sulphur among the following is -

In the preparation of compounds of Xe, Bartlett had taken ${\mathrm{O}}_2^{+} \mathrm{Pt} {\mathrm{F}}_6^{-}$ as a base compound. This is because: