What is the equivalent mass of $I{O}_4^{-}$ when it is converted into I₂ in acid medium

In an alkaline medium ClO₂ oxidize H₂O₂ in O₂ and reduces itself in Cl^– . How many moles of H₂O₂ will be oxidized by one mole of ClO₂?

Oxidation number of oxygen in potassium super oxide (KO₂) is-

The oxidation state of Cu in  ${\mathrm{YBa}}_2{\mathrm{Cu}}_3{\mathrm{O}}_7$  is -

(Yttrium = +3)

In a balanced equation $H_{2}S{O}_4+xHI\to H_{2}S+y{I}_2+z{H}_{2}O$, the values of x, y, z are -

When $Mn{O}_2$ is fused with KOH, a coloured compound is formed, the product and its colour is [IIT Screening 2003]

A compound contains three elements A, B and C, if the oxidation number of A =+2, B =+5 and C =-2, the possible formula of the compound is :

Assertion : The ratio by volume of gaseous reactants and products is in agreement with their

                   molar ratio.

Reason : Volume of a gas is inversely proportional to the number of moles of a gas.

Equivalent weight of ${\mathrm{FeS}}_2$ in the half reaction, ${\mathrm{FeS}}_2 \stackrel{}{\to } {\mathrm{Fe}}_2{\mathrm{O}}_3+{\mathrm{SO}}_2$ is:

The equivalent weight of $\mathrm{HCl}$ in the given reaction is: ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7+14\mathrm{HCl} \to 2\mathrm{KCl}+2{\mathrm{CrCl}}_3+3{\mathrm{Cl}}_2+{\mathrm{H}}_2\mathrm{O}$

The change in oxidation number of chlorine when Cl₂ gas reacts with hot and concentrated sodium hydroxide solution is -

 $$\begin{gathered} {\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{4-}\to {\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{3-}+{\mathrm{e}}^{-}; {\mathrm{E}}^{\mathrm{o}}=-0.35 \mathrm{V} \\ {\mathrm{Fe}}^{2+}\to {\mathrm{Fe}}^{3+}+{\mathrm{e}}^{-}; {\mathrm{E}}^{\mathrm{o}}=-0.77 \mathrm{V} \end{gathered}$$
The strongest oxidizing agent in the above equation is -

Number of moles of  $Mn{O}_4^{-}$required to oxidise one mole of ferrous oxalate completely in acidic medium will be

The number of moles of KMnO₄ that will be needed to react with one mole of sulphite ion in an acidic solution is :

Which of the following displays a disproportional reaction?

(a)  $2{\mathrm{Cu}}^{+} \to {\mathrm{Cu}}^{2+}+{\mathrm{Cu}}^0$

(b)  $3{\mathrm{MnO}}_4^{2-}+4{\mathrm{H}}^{+} \to 2{\mathrm{MnO}}_4^{-}+{\mathrm{MnO}}_2+2{\mathrm{H}}_2\mathrm{O}$

(c)  $2{\mathrm{KMnO}}_4 \stackrel{∆}{\to } {\mathrm{K}}_2{\mathrm{MnO}}_4+{\mathrm{MnO}}_2+{\mathrm{O}}_2$

(d)  $2{\mathrm{MnO}}_4^{-}+3{\mathrm{Mn}}^{2+}+2{\mathrm{H}}_2\mathrm{O} \to 5{\mathrm{MnO}}_2+4{\mathrm{H}}^{\oplus }$

KMnO₄ (mol. wt=158) oxidizes oxalic acid in acidic medium to CO₂ and water as follows.

$5{\mathrm{C}}_2{\mathrm{O}}_4^{2-}+2{\mathrm{MnO}}_4^{-}+16{\mathrm{H}}^{+}\to 10{\mathrm{CO}}_2+2{\mathrm{Mn}}^{2+}+8{\mathrm{H}}_2\mathrm{O}$

What is the equivalent weight of KMnO₄?

Read the following statements (S) and Explanation (E). Choose the correct answers from the codes (1), (2), (3) and (4):

S : ${\mathrm{H}}_3{\mathrm{BO}}_3$ is monobasic Lewis acid but salt ${\mathrm{Na}}_3{\mathrm{BO}}_3$ exist.

E : ${\mathrm{H}}_3{\mathrm{BO}}_3$ reacts with $\mathrm{NaOH}$ to give ${\mathrm{Na}}_3{\mathrm{BO}}_3$.

  P₄ + NaOH → PH₃ + NaH₂PO₂

The correct statement among the following is -

The oxidation number of Ba in barium peroxide is :

Maximum oxidation state of Cr is :

The oxidation number of Cr in ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ is:

Oxidation state of oxygen in hydrogen peroxide is :

$2{\mathrm{MnO}}_4^{-}+5{\mathrm{H}}_2{\mathrm{O}}_2+6{\mathrm{H}}^{+}\to 2 \mathrm{Z}+5{\mathrm{O}}_2+8{\mathrm{H}}_2\mathrm{O}$. In this reaction Z is :

Which of the following is the most powerful oxidizing agent ?

Nitrogen show different oxidation states in the range :

How many moles of ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ can be reduced 1 mole of ${\mathrm{Sn}}^{2+}$?\

${\mathrm{MnO}}_4^{2-}$ (1 mole ) in neutral aqueous medium is disproportionate to :

3. 1/3 mole of ${\mathrm{Mn}}_2{\mathrm{O}}_7$ and 1/3 mole of ${\mathrm{MnO}}_2$

The oxidation number of oxygen in ${\mathrm{KO}}_3 \mathrm{and} {\mathrm{Na}}_2{\mathrm{O}}_2$ is respectively -