Chemistry - Solid State - Quiz-5

A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal atoms in one unit cell, the radius of one atom is -

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40 pm
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127 pm
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80 pm
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108 pm

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^–3. The molar mass of the metal is :

(N_A Avogadro's constant = 6.02 × 10²³ mol^–1)

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30 g mol^–1
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27 g mol^–1
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20 g mol^–1
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40 g mol^–1

A metal crystallizes with a fcc lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is :

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288 pm
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408 pm
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144 pm
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204 pm

The number of octahedral void(s) per atom present in a cubic close-packed structure is :

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1
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3
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2
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4

Sodium has body centered packing. Distance between two nearest atoms is 3.7 Å . The lattice parameter is -

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6.8 Å
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4.3 Å
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3.0 Å
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8.5 Å

If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius in fcc crystal is :

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1.81 Å
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2.10 Å
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2.92 Å
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1.27 Å

Percentage of free space in a body centred cubic unit cell is -

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30%
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32%
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34%
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28%

Silicon give p-type of semiconductor on dope with -

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Germanium.
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Arsenic.
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Selenium.
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Boron.

For a cubic crystal structure which one of the following relations indicating the cell characteristic is correct?

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$a \neq b \neq c a n d α \neq β a n d γ \neq 90 °$
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$a \neq b \neq c a n d α = β = γ = 90 °$
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$a = b = c a n d α \neq β = γ = 90 °$
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$a = b = c a n d α = β = γ = 90 °$

CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02×10²³ mol^-1, the density of CsBr is :

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42.5 $g / c m^{3}$
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0.425 $g / c m^{3}$
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8.25 $g / c m^{3}$
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4.25 $g / c m^{3}$

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is:

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$C_{3} A_{4}$
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$C_{2} A_{3}$
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$C_{3} A_{2}$
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$C_{4} A_{3}$

Ionic radii of Mg²⁺ and O^2- ions are 66 pm and 140 pm respectively. The type of interstitial void and coordination number of Mg²⁺ ion respectively are

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Tetrahedral, 12
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Octahedral, 6
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Tetrahedral, 6
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Octahedral, 8

An element crystallizes in a structure having FCC unit cell of an edge length 200 pm. If
200 g this element contains 24 x 10²³ atoms, the density of the element is

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50.3 g/cc
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63.4 g/cc
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41.6 g/cc
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34.8 g/cc

A cube of any crystal A-atom placed at every corners and B-atom placed at every centre of face. The formula of compound is :

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AB
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AB₃
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A₂B₂
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A₂B₃

Schottky defect shows :

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Same number of cation and anions decrease from lattice.
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Cations and anions are replaces from their sites.
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Maximum number of cations and anions are same.
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None of the above.

A compound formed by elements X and Y crystallizes in a cubic structure in which the X atoms are at the corners of a cube and the Y atoms are at the face-centers. The formula of the compound is :-

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X₃Y
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XY
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XY₂
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XY₃

In the spinel structrue, oxides ions are cubical-closest packed whereas 1/8th of tetrahedral voids are occupied by $A^{2 +}$ cation and 1/2 of octahedral voids are occupied by $B^{3 +}$ cations. The general formula of the compound having spinel structure is :

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$A_{2} B_{2} O_{4}$
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${AB}_{2} O_{4}$
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$A_{2} B_{4} O_{2}$
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$A_{4} B_{2} O_{2}$

A compound that shows Schottky as well as Frenkel defect among the following is -

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ZnS
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AgBr
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NaCl
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AgCl

The edge length of fcc unit cell of NaCl is 508 pm.
If the radius of cation is 110 pm then radius of the anion is :

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244 pm
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144 pm
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288 pm
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398 pm

The formula of nickel oxide with metal deficiency defect in its crystal is $N i_{0.98} O$ . The crystal contains ${Ni}^{2 +} and {Ni}^{3 +}$ ions. The fraction of nickel existing as $N i^{2 +}$ ions in the crystal is-

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0.96
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0.04
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0.50
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0.31

An ionic compound has a unit cell consisting of A ions at the corners of a cube and B
ions on the centers of the faces of the cube. The empirical formula for this compound
would be :

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AB
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A₂B
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AB₃
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A₃B

An element occurring in the bcc structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be:

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$24.16 \times 10^{23}$
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$36.18 \times 10^{23}$
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$6.04 \times 10^{23}$
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$12.08 \times 10^{23}$

If an element (at. Wt. = 50) crystallises in fcc lattice, with a = 0.50 nm.The density of unit cell if it contains 0.25% Schottky defects is -

(Use $N_{A} = 6 \times 10^{23}$ )

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2.0 g/cc
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2.66 g/cc
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3.06 g/cc
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None of the above.

An element has a body-centered cubic (BCC) structure with a cell edge of 288 pm. The atomic radius is:

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$\frac{\sqrt{2}}{4} \times 288$ pm
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$\frac{4}{\sqrt{3}} \times 288$ pm
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$\frac{4}{\sqrt{2}} \times 288$ pm
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$\frac{\sqrt{3}}{4} \times 288$ pm

Assertion: Due to Frenkel defect, density of the crystalline solid decreases.
Reason: in Frenkel defect cation and anion leaves the crystal.

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Both assertion and reason are true and reason is the correct explanation of assertion.
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Both assertion and reason are true but reason is not the correct explanation of assertion.
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Assertion is true but reason is false.
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Both assertion and reason are false.

The crystal with a metal deficiency defect is -

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NaCl
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FeO
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ZnO
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KCl

The radius ratio (r⁺/r^-) of KF is 0.98. The structure of KF is similar to

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NaCl
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CsCl
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ZnS
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Both 1 and 2

A compound formed by elements A and B crystallizes in cubic structure where A atoms are at the corners or a cube and B atoms are at the face centre. The formula of the compound is :

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AB
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AB₂
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AB₃
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AB₄

ln NaCl, the chloride ions occupy the space in a Fashion of

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BCC
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FCC
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Both
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None of the above

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Practice Chemistry Quiz Questions and Answers

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Practice Chemistry Quiz Questions and Answers

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