The density of 68% nitric acid by mass in an aqueous solution is 1.504 g mL-1. The molarity of the acid solution would be -
15.24 M
16.23 M
14.52 M
13.45 M
A solution of glucose (M.W =180 g mL-1) in water is 10% w/w. The mole fraction of each component in the solution is -
Mole fraction of glucose - 0.44; Mole fraction of water - 0.56
Mole fraction of glucose - 0.056; Mole fraction of water - 0.944
Mole fraction of glucose - 0.011; mole fraction of water - 0.99
Mole fraction of glucose - 0.36; mole fraction of water - 0.64
An antifreeze solution is prepared from 222.6 g of ethylene glycol C2H6O2 and 200g of water. The molality of the solution would be -
6.9 m
17.9 m
29.9 m
21.9 m
A sample of drinking water was contaminated with chloroform. The level of contamination was 15 ppm (by mass). The mass percent of chloroform is-
15×10-4
1.5×10-4
0.15×10-4
15×10-5
The type of molecular interactions in a solution of alcohol and water is -
Electrostatic interaction
London dispersion forces
Hydrogen bonding
Ion-dipole interaction
The graph representing Henry's law is given below:
The value of the slope will be
1. 4×10-4 torr2. 5×10-4 torr3. 4×104 torr4. 5×104 torr
Consider the following graph:
Point A and B in the above mentioned graph represent, respectively
Partial pressures of first and second components
Vapour pressures of the pure second and first components
Partial pressures of second and first components
Vapour pressures of the pure first and second components
The law represented by given graph is -
Henry's law
Raoult's law
Boyle's law
Charle's law
The graph, amongst the following, representing positive deviation of vapour pressure is-
None of the above
The correct graph, amongst the following, that represents the elevation in boiling point is -
4. None of the above.
The following solutions were prepared by dissolving 10g of glucose (C6H12O6) in 250 ml of water (P1). 10g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The decreasing order of osmotic pressure of these solutions is:
P2>P3>P1
P3>P1>P2
P2>P1>P3
P1>P2>P3
The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in a molar ratio 3:2 is :
[At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
336 mm of Hg
350 mm of Hg
160 mm of Hg
168 mm of Hg
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