A solution of acetone in ethanol is-
Shows a negative deviation from Raoult's law
Shows a positive deviation from Raoult's law
Behaves like a near ideal solution
Obeys Raoult's law
Three solutions are prepared by adding 'w' gm of 'A' into 1kg of water, 'w' gm of 'B' into another 1 kg of water and 'w' gm of 'C' in another 1 kg of water (A, B, C are non electrolytic). Dry air is passed from these solutions in sequence (A → B → C). The loss in weight of solution A was found to be 2gm while solution B gained 0.5 gm and solution C lost 1 gm. Then the relation between molar masses of A, B and C is :
MA: MB : Mc = 4 : 3 : 5
MA : MB: Mc = 14:13:15
Mc > MA > MB
MB > MA> Mc
How many mili moles of sucrose should be dissolved in 500 gms of water so as to get a solution which has a difference of 103.57°C between boiling point and freezing point.
(K1 = 1.86 K Kg mol−1, Kb = 0.52 K Kg mo1−1)
500 mmoles
900 mmoles
750 mmoles
650 mmoles
The molar heat of vapourization of toluene is AHv. If its vapour pressure at 315 K is 60 torr & that at 356K is300 torr then AHv = ? (log 2 = 0.3)
37.5 kJ/mole
3.75 kJ/mole
37.5 J/mol
3.75 J/mole
Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl) Cl in 3 moles H2O is 0.50. On reaction with AgNO3, this solution will form (assuming no change in degree of ionisation of substance on adding AgNO3)
1 mol AgCl
0.25 mol AgCl
0.5 mol AgCl
0.40 mol AgCl
Which of the following has been arranged in order of decreasing freezing point?
0.05 M KNO3 > 0.04 M CaCl2 > 0.140 M sugar > 0.075 M CuSO4
0.04 M BaCl2 > 0.140 M sucrose > 0.075 M CuSO4 > 0.05 M KNO3
0.075 MCuSO4 > 0.140 M sucrose > 0.04 M BaCl2 > 0.05 M KNO3
0.075 M CuSO4 > 0.05 M NaNO3 > 0.140 M sucrose > 0.04 M BaCl2
A solution of x moles of sucrose in 100 grams of water freezes at −0.2°C. As ice separated the freezing point goes down to 0.25°C. How many grams of ice would have separated?
10 grams
20 grams
25 grams
23 grams
An ideal mixture of liquids A and B with 2 moles of A and 2 moles of B has a total vapour pressure of 1 atm at a certain temperature. Another mixture with 1 mole of A and 3 moles of B has a vapour pressure greater than 1 atm. But if 4 moles of C are added to the second mixture, the vapour pressure comes down to 1 atm. Vapour pressure of C, Pc° = 0.8 atm. Calculate the vapour pressures of pure A and pure B.
(1) PA° = 4 atm, PB° = 0.7 atm
(2) PA = 1.2 atm, PB° = 0.6 atm
(3) PA = 1.4 atm, PB° = 0.6 atm
(4) PA° = 0.6 atm, PB° = 1.4 atm
A sample of air is saturated with benzene (vapor pressure = 100 mm Hg at 298 K) at 298K, 750mm Hgpressure. If it is isothermally compressed to one third of its initial volume, the final pressure of the system is
2250 torr
2150 torr
2050 torr
1950 torr
Available solutions are 1L of 0.1 M NaCl and 2L of 0.2 M CaCl2. Using only these two solutions what maximum volume of a solution can be prepared having [Cl–] = 0.34M exactly. Both electrolytes are strong
2.5 L
2.4 L
2.3 L
None of these
Consider equimolal aqueous solutions of NaHSO4 and NaCl with ∆Tb and ∆T'b as their respective boiling point elevations. The value of limx→0 ΔTbΔTb' will be :
1
1.5
3.5
3
The vapor pressures of benzene, toluene and a xylene are 75 Torr, 22 Torr and 10 Torr at 20°C. Which of the following is not a possible value of the vapor pressure of an equimolar binary/ternary solution of these at 20°C ? Assume all form ideal solution with each other.
4812
16
3523
5312
Osmotic pressure is 0.0821 atm at a temperature of 300 K. Find concentration in mole/litre [Roorkee 1990]
0.033
0.066
0.33 × 10–2
The osmotic pressure of 5% (mass-volume) solution of cane sugar at 150°C (mol. mass of sugar = 342) is-
4 atm
5.07 atm
3.55 atm
2.45 atm
3.24 g of Hg(NO3)2 (molar mass = 324) dissolved in 1000 g of water constitutes a solution having a freezing point of –0.0558°C while 21.68 g of HgCl2 (molar mass = 271) in 2000 g of water constitutes a solution with a freezing point of –0.0744°C. The Kf for water is 1.86 K – KgMol. About the state of ionization of these two solids in water it can be inferred that:
Hg(NO3)2 and HgCl2 both are completely ionized
Hg(NO3)2 is fully ionized but HgCl2 is fully unionized
Hg(NO3)2 and HgCl2 both are completely unionized
Hg(NO3)2 is fully unionized but HgCl2 is fully ionized
15 g of methyl alcohol is dissolved in 35 g of water. The weight percentage of methyl alcohol in solution is
70%
30%
50%
75%
The seawater sample contains 5.8 × 10–3 g of dissolved oxygen per kilogram of the sample. The concentration of oxygen in parts per million is-
5.8 ppm
58.5 ppm
0.58 ppm
0.05 ppm
A 500 gm toothpaste sample has 0.2 g fluoride concentration. The concentration of fluoride ions in terms of ppm level is
250 ppm
200 ppm
400 ppm
1000 ppm
Normality of a solution containing 9.8 g of H2SO4 in 250 cm3 of the solution is
[MP PMT 1995, 2003; CMC Vellore 1991; JIPMER 1991]
0.8 N
1 N
0.08 N
1.8 N
Amount of NaOH present in 200 ml of 0.5 N solution is
40 g
4 g
0.4 g
4.4 g
50 ml of 10N H2SO4, 25ml of 12 N HCl and 40 ml of 5N HNO3 were mixed together and the volume of the mixture was made 1000 ml by adding water. The normality of the resulting solution will be
2 N
3 N
4 N
100 ml of 0.3 N HCl is mixed with 200 ml of 0.6 N H2SO4. The final normality of the resulting solution will be
0.1 N
0.2 N
0.3 N
0.5 N
An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 ml. The volume of 0.1 N NaOH required to completely neutralize 10 ml of this solution is [IIT 2001; CPMT 1986]
40 ml
20 ml
10 ml
4 ml
10.6 g of Na2CO3 was exactly neutralised by 100 ml of H2SO4 solution. Its normality is
1.5 N
The molarity of pure water (d = 1 g/l) is -
555 M
5.55 M
55.5 M
None of the above
Equal volumes of 0.1M AgNO3 and 0.2 M NaCl are mixed. The concentration of NO3− ions in the mixture will be
0.1 M
0.05 M
0.2 M
0.15 M
The molarity of H2SO4 solution that has a density of 1.84 g/cc at 35°C and contains 98% by weight is
4.18 M
8.14 M
18.4 M
18 M
Amount of oxalic acid (COOH)2.2H2O in grams that is required to obtain 250 ml of a semi-molar solution is
17.25 g
17.00 g
15.75 g
15.00 g
Volume of 10 M HCl should be diluted with water to prepare 2.00 L of 5 M HCl is
2 L
1.5 L
1.00 L
0.5 L
The volume of 95% H2SO4 (density = 1.85 g cm–3) needed to prepare 100 cm3 of 15% solution of H2SO4 (density = 1.10 g cm3) will be
5 cc
7.5 cc
9.4 cc
12.4 cc
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