600 cc of a gas at a pressure of 750 mm is compressed to 500 cc. Taking the temperature to remain constant, the increase in pressure is-
150 mm
250 mm
350 mm
450 mm
The curve that can not represent Boyle's law is -
The deviation of a gas from ideal behavior is expected to be minimum at -
350 K and 3 atm
550 K and 1 atm
250 K and 4 atm
450 K and 2 atm
An ideal gas expands according to PV=constant. On expansion, the temperature of the gas:
Will rise
will drop
Will remain constant
Cannot be determined because the external pressure is not known
The correct statement for an ideal gas equation is -
n is the number of molecules of a gas
V denotes the volume of 1 mole of the gas
n moles of a gas has a volume V
p is the pressure of the gas when only one mole of the gas is present
The gas among the following that can be most steadily liquefied is -
NH3
Cl2
SO2
CO2
Internal energy and pressure of a gas per unit volume are related as
p= 23E
p = 32E
p=12E
p = 2E
If a gas expands at constant temperature, it indicates that
kinetic energy of molecules decreases
pressure of the gas increases
kinetic energy of molecules remains the same
number of the molecules of gas increases
The condition of SATP refers to:
25 °C and 2 atm
25 °C and 1 atm
0 °C and 2 atm
25 °C and 1 bar
While He is allowed to expand through a small jet under adiabatic condition heating effect is observed. This is due to the fact that:
helium is an inert gas
helium is a noble gas
helium is an ideal gas
the inversion temperature of helium is very low
The ratio among most probable velocity, mean velocity, and root mean square velocity is given by
1:2:3
1: 2:3
2:3:8π
2:8π:3
The condition that favour a pure sample of an ideal gas to have pressure of 1 atm and a concentration of
1 mol L-1 is -
(R=0.082 L atm mol-1deg-1)
2. When V = 22.4 L
At STP
3. When T = 12 K
Impossible under any conditions
The compressibility of a gas is less than unity at STP. Therefore:
Vm > 22.4 litre
Vm < 22.4 litre
Vm = 22.4 litre
Vm = 44.8 litre
The numerical value of cp -cv is equal to:
R
R/M
M/R
None of the above
The van der Waals' equation for real gas is:
(P + a/V2)(V-b) = RT
(P+n2a/V2)(V-nb) = nRT
P=nRT/V-nb - an2/V2
All of the above
The increase in pressure in order to decrease the volume of a gas by 5% at a constant temperature will be -
5%
5.26%
10%
4.26%
If an open container is heated from 300 K to 400 K, then the % of gas that remains in the container is-
25%
50%
75%
100%
The correct statement regarding the van der Waal constant of N2 & NH3 is -
aNH3> aN2, bNH3< bN2
aNH3< aN2, bNH3< bN2
aNH3> aN2, bNH3> bN2
aNH3 < aN2, bNH3> bN2
In which case rate of diffusion is highest if all are present in the same container at the same temerature:
4g H2
32g O2
22g CO2
56g N2
At high pressure, Vander Waal gas equation is reduced to (For 1 mole of gas)
Z = 1- a/RTV
PV = RT +Pb
PV = RT +a/V
Z = 1- Pb/RT
Partial pressure of Hydrogen in Flask containing 2 gm of H2 and 32 gm of SO2 is-
1/16 of total pressure
1/2 of total pressure
2/3 of total pressure
1/8 of total pressure
At high pressure, the compressibility factor 'Z' is equal to-
Unity
1-PbRT
1+PbRT
Zero
At constant temperature, 200 cm3 of N2 at 720 mm and 400 cm3 of O2 at 750 mm pressure are put together in a one-litre flask. The final pressure of the mixture is-
111 mm
222 mm
333 mm
444 mm
The rate of diffusion of two gases A and B is in the ratio of 1:4 and the B and C in the ratio 1:3 the rate of diffusion of C with respect to A is
1/12
12
3
4
A sample of air contains only N2, O2 and H2O. It is saturated with water vapours and the total pressure of 640 torr. The vapoure pressure of water is 40 torr and the molar ratio of N2:O2 is 3:1. The partial pressure of N2 in the sample in
480 torr
600 torr
525 torr
450 torr
The temperature at which the r.m.s velocity of carbon dioxide becomes the same as that of nitrogen at 210C is-
273K
4620C
1890C
546K
At what temperature will the total K.E. of 0.3 mol of He be the same as the total K.E. of 0.4 mol of Ar at 400 K
400K
300K
346K
533K
The density of O2(g) is maximum at-
STP
273 K and 2 atm
546 K and 1 atm
546 K and 2 atm
20 L of SO2 diffuses through a porous partition in 60s. Volume of O2 diffuse under similar condition in 30s will be:-
12.14 L
14.14 L
18.14 L
28.14 L
In van der Waal's equation of state for a non-ideal gas, the term that accounts for the intermolecular force is-
(P+a/V2)
RT
(RT)-1
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