The internal energy change when a system goes from state A to B is 40 kJ/mol. If the system goes from A to B by a reversible path and returns to state A by an irreversible path. What would be the change in internal energy?
40 kJ
>40 kJ
<40 kJ
Zero
Change in entropy is negative for:
Bromine (l)→Bromine(g)
C(s) + H2O(g) →CO(g) + H2(g)
N2(g,10 atm)→N2(g,1 atm)
Fe ( 1mol, 400 K) → Fe( 1mol, 300 K)
The mathematical form of the first law of thermodynamics when heat (q) is supplied and W is work done by the system (-ve) is:
∆U=q+W
∆U=q-W
∆U=-q+W
∆U= -q-W
Which statements are correct?
unavailable energy = entropy x temperature
2.303 logP2P1=∆Hvap.RT2-T1T1T2 is called Clausius-Clapeyron equation
∆Hvap.Boiling Point=88 J mol-1K-1 is called Trouton's rule
Entropy is a measure of unavailable energy, i.e.,
All of the above
∆S° will be highest for the reaction:
Ca(s) + 1/2 O2(g) →CaO(s)
CaCO3(s)→CaO(s) + CO2(g)
C(s) + O2(g)→CO2(g)
N2(g) + O2(g)→2NO(g)
One mole of ice is converted into the water at 273 K. The entropies of H2O(s) and H2O(l) are 38.20 and 60.01 J mol-1K-1 respectively. The enthalpy change for the conversion is:
59.54 J mol-1
5954 J mol-1
595.4 J mol-1
320.6 J mol-1
The reaction CH4(g) + Cl2(g)→CH3Cl(g) + HCl(g)
has ∆H=-25 K cal
From the given data, what is the bond enthalpy of Cl-Cl bond?
70 Kcal
80 Kcal
67.75 Kcal
57.85 Kcal
Entropy decreases in which of the following reactions?
Boiling of egg
Combustion of benzene at 127°C
Stretching of rubber band
Dissolution of sugar in water
Heat of the neutralization is greater than 13.7 kcal in -
HF & NH4OH
HCl & NaOH
HI & KOH
HF & NaOH
Consider the reaction
N2(g) + 3H2(g)→2NH3(g) carried out at constant temperature and pressure. If ∆H and ∆E are enthalpy change and internal energy change respectively, which of the following expression is True?
1. ∆H⩾∆E 2. ∆H=∆E3. ∆H<∆E 4. ∆H>∆E
Work done is maximum in -
Isobaric work
Isothermal work
Isochoric work
Adiabatic work
For exothermic reaction to be spontaneous (∆S=negative) temperature must be -
High
Constant
Low
Which of the following conditions should be satisfied for the given reaction to be spontaneous at 0°C and 1 atm?
H2O(s) ⇌H2O(l)
∆H=∆G
∆H<T.∆S
∆H>T.∆S
∆H=T.∆S
'The free energy change due to a reaction is zero when-
The reactants are initially mixed.
A catalyst is added
The system is at equilibrium
The reactants are completely consumed
An ideal gas expands at a constant external pressure of 2.0 atmosphere by 20 litre and absorbs 10kJ of heat from surrounding. What is the change in internal energy of the system:-
4052 J
5948 J
14052 J
9940 J
36 ml of pure water takes 100 sec to evaporate from a vessel and heater connected to an electric source which delivers 806 watt. The ∆Hvaporisation of H2O is:-
40.3 kJ/mol
43.2 kJ/mol
4.03 kJ/mol
None of these
5 moles of an ideal gas expands isothermally and irreversibly from a pressure of 10 atm to 1 atm against a constant external pressure of 1 atm. find the Wirr at 300 K:-
-15.921 kJ
-11.224 kJ
-110.83 kJ
In the reaction at 300 K
H2(g) + Cl2(g)→2HCl(g) ∆H°= -185 kJ
if 2 mol of H2 completely react with 2 mole of Cl2 to form HCl. What is ∆U° for this reaction?
0
-185 kJ
-370 kJ
Predict which of the following reaction(s) has a positive entropy change?
(i) Ag+ (aq) + Cl-(aq) →AgCl(s)
(ii) NH4Cl(g) →NH3(g) + HCl(g)
(iii) 2NH3(g)→N2(g) + 3H2(g)
i & ii
iii
ii & iii
ii
When two moles of an ideal gas (Cp, m=52R) heated from 300 K to 600 K at constant pressure the change in entropy of gas (∆S) is:-
32Rln2
-32Rln2
7R ln 2
5 Rln2
The free energy change ∆G=0 when:-
Catalyst is added
Reactants are initially mixed throughly
For isothermal expanison in case of an ideal gas:-
∆G=∆S
∆G=∆H
∆G=-T∆S
At 25°C, for the process H2O(l)⇌H2O(g);
∆G° is 8.6 kJ. The vapour pressure of water at this temperature is nearly:-
24 torr
285 torr
32.17 torr
100 torr
What will be the standard enthalpy of reaction for the following reaction using the listed enthalpies of reaction:-
3Co(s) + 2O2(g)→Co3O4(s); ∆H=?
2Co(s) + O2(g) →2CoO(s) ∆H1= -475.8 KJ
6CoO(s) + O2(g) →2Co3O4(s) ∆H2 = -355.0 KJ
(1) -892 KJ
(2) -120.8 KJ
(3) 891.2 KJ
(4) -830.8 KJ
The standard enthalpy of vaporisation ∆vapH° for water at 100°C is 40.66 kJ mol-1. The
internal energy of vaporisation of water at 100°C (in kJ mol-1) is-
(Assume water vapour to behave like an ideal gas)
+37.56
-43.76
+43.76
+40.66
For given following equations and ∆H° values, determine the enthalpy of reaction at 298 K for the reaction
C2H4(g) + 6F2(g) → 2CF4(g) + 4HF(g)
H2(g) + F2(g) → 2HF(g) ∆H1°= -537 kJ
C(s) + 2F2(g) →CF4(g) ∆H2°=-680 kJ
2C(s) + 2H2(g) →C2H4(g) ∆H3°= 52 kJ
-1165
-2486
+1165
+2486
If ∆Hf°(C2H4) and ∆Hf°(C2H6) are x1 and x2 kcal/mol then heat of hydrogenation of C2H4 is :-
x1 + x2
x1 - x2
x2 - x1
x1 + 2x2
For oxidation of iron, 4Fe(s) + 3O2(g) →2Fe2O3(s), ∆Hr°=-1648x103 J mol-1 and entropy change is -549.4 J k-1mol-1 at 298 K:-
The reaction is
Spontaneous
Non spontaneous
At Equilibrium
Can't predict
18 g of ice is converted into water at 0°C and 1 atm. The entropy of H2O(s) and H2O(l) are 38.2 and 60 J K-1 mol-1 respectively. the enthalpy for this conversion will be
(1) 5954 J/mol
(2) 595.14 J/mol
(3) -595.14 J/mol
(4) None of these
One mole of methanol when burnt in O2 gives out 723 kJ mol-1 heat. If one mole of O2 is used, what will be the amount of heat evolved?
482 kJ
723 kJ
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