If the bond energies of H-H, Br-Br, and H-Br are 433, 192 and 364 kJ mol-1 respectively,
the ∆H° for the reaction
H2(g) + Br2(g) →2HBr(g) is
-103 kJ
-261 kJ
+103 kJ
+261 kJ
For a given reaction, ∆H =35.5 kJ mol-1 and ∆S = 83.6JK-1 mol-1. The reaction is spontaneous at:(Assume that ∆H and ∆S do not vary with temperature)
A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ∆U of the gas in joules will be
1136.25 J
- 500 J
- 505 J
+ 515 J
For a sample of perfect gas when its pressure is changed isothermally from pi to pf, the entropy change is given by
∆S = nRln(pf/pi)
∆S = nRln(pi/pf)
∆S = nRTln(pf/pi)
∆S = RTln(pf/pi)
The correct thermodynamic conditions for the spontaneous reaction at all temperatures is
(a) ∆H>0 and ∆S<0(b) ∆H<0 and ∆S>0(c) ∆H<0 and ∆S<0(d) ∆H<0 and ∆S=0
The heat of combustion of carbon to CO2 is -393.5 kJ/mol. The heat released upon the
formation of 35.2 g of CO2 from carbon and oxygen gas is
-315 kJ
+315 kJ
-630 kJ
-3.15 kJ
For the reaction, X2O4(l) →2XO2(g)
∆U = 2.1 kcal, ∆S = 20 cal K-1 at 300 K. Hence, ∆G is
2.7 kcal
-2.7 kcal
9.3 kcal
-9.3 kcal
If the enthalpy change for the transition of liquid water to steam is 30 kJ mol-1 at 27°C,
the entropy change for the process would be
1.0 J mol-1 K-1
0.1 J mol-1K-1
100 J mol-1K-1
10 J mol-1K-1
For which process will ∆H° and ∆G° be expected to be most similar.
2Al(s) + Al2O3(s) → 2Fe(s) + Al2O3(s)
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
2NO2(g) → N2O4(g)
2H2(g) + O2(g) → 2H2O(g)
In thermodynamics, a process is called reversible when
Surroundings and system change into each other
There is no boundary between the system and the surroundings
The surroundings are always in equilibrium with the system
The system changes into the surroundings spontaneously
Which of the following is correct option for free expansion of an ideal gas under adiabatic condition?
(1) q≠0, ∆T =0, W=0(2) q=0, ∆T =0, W=0(3) q=0, ∆T <0, W≠0(4) q=0, ∆T≠0, W=0
Enthalpy change for the reaction,
4H(g) →2H2(g) is -869.6 kJ
The dissociation energy of H-H bond is
-869.6 kJ
+ 434.8 kJ
+217.4 kJ
-434.8 kJ
From the following bond energies:
H-H bond energy: 431.37 kJ mol-1
C=C bond energy : 606.10 kJ mol-1
C-C bond energy : 336.49 kJ mol-1
C-H bond energy : 410.50 kJ mol-1
Enthalpy for the reaction,
C|H|H=C|H|H+H-H→H-C|H|H-C|H|H-H
will be
1523.6 kJ mol-1
-243.6 kJ mol-1
-120.0 kJ mol-1
553.0 kJ mol-1
The values of ∆H and ∆S for the reaction,
C(graphite) + CO2(g) →2CO(g) are 170 kJ and 170 JK-1, respectively. This reaction will
be spontaneous at
710 K
910 K
1110 K
510 K
Which of the following are not state functions?
(I) q + W (II) q
(III) W (IV) H-TS
(I) and (IV)
(II), (III) and (IV)
(I) , (II) and (III)
(II) and (III)
Consider the following reactions :
(i) H+(aq) + OH-(aq) = H2O(l) ∆H = -x1 kJ mol-1
(ii) H2(g) + 12O2(g) = H2O(l) ∆H = -x2 kJ mol-1
(iii) CO2(g) + H2(g) = CO(g) + H2O(l) ∆H = -x3 kJ mol-1
(iv) C2H5(g) + 52O2(g) = 2CO2(g) + H2O(l) ∆H = -x4 kJ mol-1
Enthalpy of formation of H2O(l) is:
-x2 kJ mol-1
+x3 kJ mol-1
-x4 kJ mol-1
-x1 kJ mol-1
Identify the correct statement for change of Gibbs energy for a system (∆Gsystem) at constant temperature and pressure:
If ∆Gsystem > 0, the process is spontaneous
If ∆Gsystem = 0, the system has attained equilibrium
If ∆Gsystem = 0, the system is still moving in a particular direction
If ∆Gsystem < 0, the process is not spontaneous
The enthalpy and entropy change for the reaction :
Br2 (l) + Cl2 (g)→ 2BrCl (g)
are 30 kJ mol-1 and 105 J K-1 mol-1 respectively.
The temperature at which the reaction will be in equilibrium is :
285.7 K
273.4 K
450.9 K
300.1 K
The enthalpy of combustion of H2, cyclohexene (C6H10) and cyclohexane (C6H12) are -241, -3800 and -3920 kJ per mol respectively. Heat of hydrogenation of cyclohexene is:
() -121 kJ per mol
() +121 kJ per mol
() +242 kJ per mol
() -242 kJ per mol
Consider the reactionat 300K
H2(9) + Cl2(9) →2HCI(g), ΔH° = — 185 KJ
If 3 mole of H2 completely react with 3 mol of Cl2 to form Cl, ∆U° of the reaction will be
Zero
–185 KJ
-555 KJ
None
For a perfectly crystalline solid Cpm = aT3, where a is constant. If Cpm is 0.42 J/K–mol at 10 K, molar entropy at 10 K is
0.42 J/K–mol
0.14 J/K–mol
4.2 J/K–mol
zero
One mole of an ideal monoatomic gas expands isothermally against constant external pressure of 1 atm from initial volume of 1L to a state where its final pressure becomes equal to external pressure. If initial temperature of gas is 300 K then total entropy change of system in the above process is :
[R = 0.082 L atm mol–1 K–1 = 8.3 J mo1–1K–1].
0
Rln (24.6)
Rln (2490)
32Rln(24.6)
At 1000 K water vapour at 1 atm. has been found to be dissociated into H2 and O2 to the extent of 3 x 10–6 %.Calculate the free energy decrease of the system, assuming ideal behaviour.
–ΔG = 90,060 cal
–ΔG = 20 cal
–ΔG = 480 cal
–ΔG = –45760 cal
An ideal gas is taken from the same initial pressure P1 to the same final pressure P2 by three different processes. If it is known that point 1 corresponds to a reversible adiabatic and point 2 corresponds to a single stage adiabatic then
Point 3 may be a two stage adiabatic.
the average K.E. of the gas is maximum at point 1
Work done by surrounding in reaching point number '3' will be maximum
If point4 and point 5 lie along a reversible isotherm then T5 < T1.
During winters, moisture condenses in the form of dew and can be seen on plant leaves and grass. The entropy of the system in such cases decreases as liquids possess lesser disorder as compared to gases. With reference to the second law, which statement is correct, for the above process ?
The randomness of the universe decreases
The randomness of the surroundings decreases
Increase is randomness of surroundings equals the decrease in randomness of system
The increase in randomness of the surroundings is greater as compared to the decrease in randomnessof the system.
The occurrence of a reaction is impossible if -
ΔH is +ve ; ΔS is also + ve but ΔH < TΔS
ΔH is – ve ; ΔS is also – ve but ΔH > TΔS
ΔH is – ve ; ΔS is + ve
ΔH is + ve ; ΔS is – ve
A copper block of mass `m' at temperature 'T1' is kept in the open atmosphere at temperature `T2' where T2 > T1 . The variation of entropy of the copperblock with time is best illustrated by
The heat produced in calories by the combustion of one gram of carbon is called
Heat of combustion of carbon
Heat of formation of carbon
Calorific value of carbon
Heat of production of carbon
For the isothermal expansion of an ideal gas
E and H increases
E increases but H decreases
H increases but E decreases
E and H are unaltered
If a refrigerator's door is opened, then we get
Room heated
Room cooled
More amount of heat is passed out
No effect on room
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